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4 years ago

Convert 150km/hr to m/sshowing its workings

Physics

1 answer:

Phantasy [73]4 years ago

3 0

150x1000 (turn km into m)
=150000m
150000 / 60 (hour to min)
=2500m/min
2500 / 60 (min to sec)
=41.6666666
=41,1/3 m/s

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a spherical mirror produces a magnification of -1 on a screen placed at a distance of 40cm from the mirror i) write the type of

Darya [45]

Answer:

f =-20 cm

Explanation:

Given that,

The magnification of a spherical mirror, m = -1

The image distance, v = 40 cm (for negative magnification)

The magnification of a concave mirror is negative. The mirror showing -1 magnification is a concave mirror.

Let f be the focal length of the mirror. We know that,

$m=\dfrac{-v}{u}\\\\-1=\dfrac{-v}{u}\\\\v=u$

Object distance, u = -40 cm

Using mirror's formula i.e.

$\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}\\\\f=\dfrac{1}{\dfrac{1}{-40}+\dfrac{1}{-40}}\\\\f=-20\ cm$

So, the focal length of the mirror is 20 cm.

8 0

3 years ago

You want to determine your speed running across the room. what is one piece of data you need

Reika [66]

The distance you run divided by how long it takes

hope this is what you waned :)

3 0

4 years ago

You are on a building with a snowball. You see your favorite physics teacher walking by about 10 m away from you. How fast must

tankabanditka [31]

You must throw the snow ball by velocity 9.43 m/s horizontally to

hit him

Explanation:

You throw the snow ball horizontally from a height 5.5 meters

Your favorite physics teacher is 10 m away from you

You hit him on the foot

1. The initial velocity of the ball is v

2. The vertical component of v is zero because you throw the ball

horizontally

3. The vertical distance h is 5.5 m

4. The horizontal distance x is 10 m

We need to find how fast you must throw the snow ball to hit him

→ h = $v_{y}$ t + $\frac{1}{2}$ g t²

→ h = -5.5 m ⇒ height below the point of thrown

→ g = -9.8 m/s²

→ $v_{y}$ = 0 ⇒ vertical component of v

→ -5.5 = (0) t + $\frac{1}{2}$ (-9.8) t²

→ - 5.5 = -4.9 t²

Divide both sides by -4.9

→ t² = 1.12245

Take √ for both sides

→ t = 1.06 seconds

→ x = $v_{x}$ t

→ $v_{x}$ = v

→ x = 10 m , t = 1.06

→ 10 = v(1.06)

Divide both sides by 1.06

→ v = 9.43 m/s

You must throw the snow ball by velocity 9.43 m/s horizontally to

hit him

Learn more:

You can learn more about velocity in brainly.com/question/13103128

#LearnwithBrainly

5 0

3 years ago

1. Calculate the total binding energy of 12

ahrayia [7]

Answer:

1. B = 79.12 MeV

2. B = -4.39 MeV/nucleon

3. B = 2.40 MeV/nucleon

4. B = 7.48 MeV/nucleon

5. B = -18.72 MeV

6. B = 225.23 MeV

Explanation:

The binding energy can be calculated using the followng equation:

$B = (Zm_{p} + Nm_{n} - M)*931 MeV/C^{2}$

<u>Where</u>:

Z: is the number of protons

$m_{p}$ : is the proton's mass = 1.00730 u

N: is the number of neutrons

$m_{n}$ : is the neutron's mass = 1.00869 u

M: is the mass of the nucleus

1. The total binding energy of $^{12}_{6}C$ is:

$B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u$

$B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV$

2. The average binding energy per nucleon of $^{24}_{12}Mg$ is:

$B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u$

<u>Where</u>: A = Z + N

$B = \frac{(12*1.00730 + 12*1.00869 - 24.305)}{(12 + 12)}*931.49 MeV/u = -4.39 MeV/nucleon$

3. The average binding energy per nucleon of $^{85}_{37}Rb$ is:

$B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u$

$B = \frac{(37*1.00730 + 48*1.00869 - 85.468)}{85}*931.49 MeV/u = 2.40 MeV/nucleon$

4. The binding energy per nucleon of $^{238}_{92}U$ is:

$B = \frac{(92*1.00730 + 146*1.00869 - 238.03)}{238}*931.49 MeV/u = 7.48 MeV/nucleon$

5. The total binding energy of $^{20}_{10}Ne$ is:

$B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u$

$B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV$

6. The total binding energy of $^{40}_{20}Ca$ is:

$B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u$

$B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV$

I hope it helps you!

8 0

3 years ago

A net force of 250 N is applied to a 20 kg object, what will it's acceleration be?

creativ13 [48]

Answer:

1N is the same as 1kgm/s2. F= ma. For m and a, enter the numbers in the appropriate units.
For m, solve F = ma: m=F/a.
Plug in some numbers for F and a, with proper units, starting with m = F/a. Substitute what I said the N is equivalent to for the N. Cancel as much as you can until kg = kg. It's effective!

*Good luck!

5 0

3 years ago

Convert 150km/hr to m/sshowing its workings​

Convert 150km/hr to m/sshowing its workings