6 meters is left because you subtract 12 meters from 6
Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = 50.4 m/s
Final speed of the ball, v = -37 m/s (As it returns)
(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :
J = -5.24 kg-m/s
(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.
W = -35.1348 Joules
Hence, this is the required solution.
Answer:
a) F = 1.26 10⁵ N, b) F = 2.44 10³ N, c) F_net = 1.82 10³ N directed vertically upwards
Explanation:
For this exercise we must use the relationship between momentum and momentum
I = Δp
F t = p_f -p₀
a) It asks to find the force
as the man stops the final velocity is zero
F = 0 - p₀ / t
the speed is directed downwards which is why it is negative, therefore the result is positive
F = m v₀ / t
F = 63.5 7.89 / 3.99 10⁻³
F = 1.26 10⁵ N
b) in this case flex the knees giving a time of t = 0.205 s
F = 63.5 7.89 / 0.205
F = 2.44 10³ N
c) The net force is
F_net = Sum F
F_net = F - W
F_net = F - mg
let's calculate
F_net = 2.44 10³ - 63.5 9.8
F_net = 1.82 10³ N
since it is positive it is directed vertically upwards
The acceleration of the leaf as it falls is zero.
Explanation:
There are to forces acting on the leaf;
(a) force of gravity acting downwards
(b)Air resistance acting upwards
At some point force of gravity acting downwards balances the force of air resistance acting upwards and thus the net force on the leaf is zero.As the net force on the leaf is zero, the acceleration of the leaf =0.
Because of this zero net force, the leaf will acquire a constant velocity after some time called as terminal velocity and will continue to move with this constant velocity.
Answer:
0.98 J
Explanation:
Use the formula KE=1/2mv² to get the answer .98 J