Answer:
wrong question
Explanation:
unit of acceleration is written in m/s which is wrong
The frequency of any wave is (speed) / (wavelength).
Frequency = (330 m/s) / (2m) = 165 per second = <em>165 Hz</em>.
Period = 1 / frequency = 1 / (165 per second) = <em>0.0061 second </em>
Answer:
the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Explanation:
Given that ;
the top speed of Cheetahs is almost 60 mph
In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2
The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
From the knowledge of Newton's Law;
we knew that ;
Force F = mass m × acceleration a
Also;
The net force
= frictional force 
so we can say that;
m×a = 
where;
the coefficient of static friction
is:



= 1.94
Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Answer:
Explanation:
The longer arm means the force needed to create the required torque is lower than for the short handled spanner.
τ = FR