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RSB [31]
3 years ago
7

What is the quality of the sound of an ambulance's siren when it moves toward a stationary hearer? What is the quality of the so

und of an ambulance's siren when it moves away from a stationary hearer?
Physics
2 answers:
mixas84 [53]3 years ago
8 0

Answer:

a. The quality of the sound would have a high pitch and thus be loud.

b. The quality of the sound would have a low pitch and thus would have a lower volume than the sound from the source.

Explanation:

Using the formula for Doppler shift f' = (v ± v')f/(v ± v") where v = speed of sound in air, v'= speed of hearer = 0 m/s (since he is stationary), v" = speed of ambulance and f = frequency of sound from ambulance

So, f' = (v ± v')f/(v ± v")

f' = (v ± 0)f/(v ± v")

f' = vf/(v ± v")

a. What is the quality of the sound of an ambulance's siren when it moves toward a stationary hearer?

Since the source (ambulance) moves towards the detector, (hearer), we would get an upwards shift in frequency. (Since our denominator has to be a minimum, so we use the minus sign for v"). <u>So, the quality of the sound would have a high pitch and thus be loud.</u>

b. What is the quality of the sound of an ambulance's siren when it moves away from a stationary hearer?

Since the source (ambulance) moves away the detector, (hearer), we would get a downward shift in frequency. (Since our denominator has to be a maximum, so we use the plus sign for v"). <u>So, the quality of the sound would have a low pitch and thus would have a lower volume than the sound from the source.</u>

Damm [24]3 years ago
4 0

Answer:

A) As the ambulance's siren moves toward a stationary hearer, the quality of sound will have a higher pitch

B) As the ambulance's siren moves away from a stationary hearer, the quality of sound will have a lower pitch.

Explanation:

From Doppler effect, the closer the source of sound gets to the observer, the higher the frequency and in turn the higher the pitch.

Meanwhile, the farther a source goes from an observer, the lower the frequency of the sound and also the lower the pitch.

Thus, as the ambulance's siren moves toward a stationary hearer, the quality of sound will have a higher pitch.

As the ambulance's siren moves away from a stationary hearer, the quality of sound will have a lower pitch.

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Answer:

The electric flux is 280\ \rm N.m^2/C

Explanation:

Given:

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The flux of the Electric Field E due to the are dA in space can be found out by using Gauss Law which is as follows

\phi=\int E.dA

where

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Now according to question we have

=EA\cos\theta \\=713\times 3.14\times 0.5^2 \times \cos60^\circ\\=280\ \rm N.m^2/C

Hence the electric flux is calculated.

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3 years ago
An emf source of 6.0V is connected to a purely resistive lamp and a current of 2.0 amperes flows. All the wires are resistance-f
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A thin film of oil of thickness t is floating on water. The oil has index of refraction no = 1.4. There is air above the oil. Wh
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Answer:

t = 120.5 nm

Explanation:

given,    

refractive index of the oil = 1.4

wavelength of the red light = 675 nm

minimum thickness of film = ?

formula used for the constructive interference

2 n t = (m+\dfrac{1}{2})\lambda

where n is the refractive index of oil

t is thickness of film

for minimum thickness

m = 0

2 \times 1.4 \times t = (0+\dfrac{1}{2})\times 675

t = \dfrac{0.5\times 675}{2\times 1.4}

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A loudspeaker in a parked car is producing sound whose frequency is 20 510 Hz. A healthy young person with normal hearing is sta
Vsevolod [243]

Answer:

The car must be moving away from the person.

Explanation:

From Doppler's Effect, we know that when a sound source moves towards a stationary observer, the apparent frequency of that sound increases. While the apparent frequency decreases if the source moves away from the stationary observer.

The audible range of frequencies for a human ear is 20 Hz to 20000 Hz. Therefore, in order for the sound of a loud speaker to be audible for the person, the frequency must decrease below 20000 Hz.

<u>Due to this reason, the car must be moving away from the person.</u>

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