I believe the answer is elements!!!!
Answer:
stone A is diamond.
Explanation:
given,
Volume of the two stone = 0.15 cm³
Mass of stone A = 0.52 g
Mass of stone B = 0.42 g
Density of the diamond = 3.5 g/cm³
So, to find which stone is gold we have to calculate the density of both the stone.
We know,


density of stone A


density of stone B.


Hence, the density of the stone A is the equal to Diamond then stone A is diamond.
<span>potential energy because it has the ability to do work
*A*</span>