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ddd [48]
3 years ago
7

An example of a radioactive isotope is carbon-12. carbon-14. neon-20. neon-22.

Physics
2 answers:
Marrrta [24]3 years ago
8 0
 Carbon-14.  he is correct 
inna [77]3 years ago
4 0
The only one on the list that I know is radioactive is Carbon-14. 
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According to the Doppler Effect, which statement is true about a sound as it approaches you and then moves away.
sukhopar [10]

Answer:

A) As the source approaches you, the waves are compressed so that the pitch of the noise increases.  

Explanation:

The Doppler Effect occurs when there is relative motion between an observer and the source of a wave. When this happens, there is an apparent shift in the frequency of the wave, as perceived by the observer. In particular, two situations can occur:

1- If the source of the wave is moving towards the observer, the waves are compressed, so that the wavelength of the wave decreases, and therefore the frequency (and so the pitch) increases

2- If the source of the wave is moving away from the observer, the waves are stretched, so that the wavelength of the wave increases, and therefore the frequency (and so the pitch) decreases

An example of Doppler Effect occurs when we hear the sound of the siren of an ambulance.

In this problem, the situation described is situation 1 (sound waves is approaching the observer), so according to the explanation above, the correct answer is

A) As the source approaches you, the waves are compressed so that the pitch of the noise increases.

3 0
4 years ago
Read 2 more answers
A 1,100 kg car comes uniformly to a stop. If the vehicle is accelerating at -1.2 m/s2 , which force is closest to the net force
boyakko [2]

Answer:

Explanation:

D

7 0
3 years ago
Read 2 more answers
How long does it take a car travelling at 80 m/s to decelerate to 18 m/s with an acceleration rate of -16m/s?
sertanlavr [38]
  • initial velocity=u=80m/s
  • Final velocity=v=18m/s
  • Acceleration=a=-16m/s^2
  • Time=t

We know

\boxed{\sf a=\dfrac{v-u}{t}}

\\ \sf\longmapsto t=\dfrac{v-u}{a}

\\ \sf\longmapsto t=\dfrac{18-80}{-16}

\\ \sf\longmapsto t=\dfrac{-62}{16}

\\ \sf\longmapsto t=3.8s

4 0
3 years ago
One way to force air into an unconscious person's lungs is to squeeze on a balloon appropriately connected to the subject. What
frozen [14]

Answer:

The force that you must exert on the balloon is 1.96 N

Explanation:

Given;

height of water, h = 4.00 cm = 4 x 10⁻² m

effective area, A = 50.0 cm² = 50 x 10⁻⁴ m²

density of water, ρ = 1 x 10³ kg/m³

Gauge pressure of the balloon is calculated as;

P = ρgh

where;

ρ is density of water

g is acceleration due to gravity

h is height of water

P = 1 x 10³ x 9.8 x 4 x 10⁻²

P = 392 N/m²

The force exerted on the balloon is calculated as;

F = PA

where;

P is pressure of the balloon

A is the effective area

F = 392 x 50 x 10⁻⁴

F = 1.96 N

Therefore, the force that you must exert on the balloon is 1.96 N

3 0
4 years ago
Pendulum A has a bob of mass m hung from the string of length L; pendulum B is identical to A except its bob has the length 2L.
GenaCL600 [577]

Answer:

f_{B}: f_{A} = \sqrt{\frac{2}{1}}

Explanation:

For pendulum A: Length = L and gravity = g

The frequency of pendulum A is given by

f = \frac{1}{2\pi }\sqrt{\frac{g}{L}}

Here, f is the frequency, L be the length

f_{A} = \frac{1}{2\pi }\sqrt{\frac{g}{L}}     ... (1)

For pendulum B: Length = 2L, gravity = g

The frequency of pendulum B is given by

f_{B} = \frac{1}{2\pi }\sqrt{\frac{g}{2L}}   .... (2)

Divide equation (1) by (2)

f_{B}: f_{A} = \sqrt{\frac{2}{1}}

5 0
3 years ago
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