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balandron [24]
3 years ago
12

An object moves with a constant velocity of 17 m/s for 200 s. How far did it move during that time?

Physics
1 answer:
Radda [10]3 years ago
6 0

17m/s for 200s

200 x 17 = 3400m

Answer: 3400m or 3.4km

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A race car exerts 18,344 N while the car travels at an acceleration of 92.54 m/s2. What is the mass of the car? (Use the formula
Maru [420]

Answer:

<h3>The answer is 198.23 kg</h3>

Explanation:

To find the mass of an object given it's mass and acceleration we use the formula

m =  \frac{f}{a}  \\

where

m is the mass

F is the force

a is the acceleration

From the question

a = 92.54 m/s²

F = 18,344 N

We have

m =  \frac{18344}{92.54}  \\  = 198.2277933...

We have the final answer as

<h3>198.23 kg</h3>

Hope this helps you

4 0
4 years ago
Read 2 more answers
What is the speed of a transverse wave in a rope of length 2.00 m and mass 60.0 g under a tension of 500 n?
drek231 [11]

The formula we can use in this case would be:

v = sqrt (T / (m / l))

Where,

v = is the velocity of the transverse wave = unknown (?)

T = is the tension on the rope = 500 N

m = is the mass of the rope = 60.0 g = 0.06 kg

 l = is the length of the rope = 2.00 m

Substituting the given values into the equation to search for the speed v:
v = sqrt (500 N/(0.06 kg /2 m)) 
v = sqrt (500 * 2 / 0.06) 
v = sqrt (16,666.67) 
<span>v = 129.10 m/s</span>

7 0
3 years ago
when an electric current is flowing through a wire which of the following is also produced energy domain field force
qaws [65]

When an electric current is flowing through a wire, there is a magnetic <em>field</em> produced.  The lines of magnetic force are circles around the wire.

4 0
4 years ago
A 47.4 kg student runs down the sidewalk and jumps with a horizontal speed of 42 m/s onto a stationary skateboard
Tpy6a [65]

Answer:

3 kg

Explanation:

Momentum before = momentum after

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

After jumping on the skateboard, the student and the skateboard have the same velocity, so v₁ = v₂.

m₁u₁ + m₂u₂ = (m₁ + m₂) v

(47.4 kg) (4.2 m/s) + m (0 m/s) = (47.4 kg + m) (3.95 m/s)

m = 3 kg

8 0
4 years ago
a trcuk weighs four times as much as a stationary car. if teh truck coasts into the car at 12 km/s and they stick toegther, what
Andrews [41]

Answer:

  v=9.6 km/s

Explanation:

Given that

The mass of the car =  m

The mass of the truck = 4 m

The velocity of the truck ,u= 12 km/s

The final velocity when they stick = v

If there is no any external force on the system  then the total linear momentum of the system will be conserve.

Pi = Pf

m x 0 + 4 m x 12 = (m + 4 m) x v

0 + 48 m = 5 m v

5  v  = 48

v=\dfrac{48}{5}\ km/s

v=9.6 km/s

Therefore the final velocity will be 9.6 km/s.

3 0
3 years ago
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