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3 years ago

Find the factored form of -14a-a^2=0

Mathematics

2 answers:

Mrac [35]3 years ago

5 0

Answer: the factored answer is 6a^2

Step-by-step explanation:

algol133 years ago

3 0

Answer its a i just did it

Step-by-step explanation:

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A company has determined that 1% of its widgets are defective. If a customer received 2 widgets, what is the probability that th

Vsevolod [243]

Assume independence because there are probably a lot of widgets. 1/100 x 1/100 = 1/10,000

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3 years ago

What is 4 over 6 divided by 2 over 4?

djverab [1.8K]

4/3 /......................................................../

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3 years ago

Michelle, lori, and patti buy lunch together. The total bill was $45. If michelle pays 35% of the total bill and lori pays 48% o

siniylev [52]

Answer:

$7.65

Step-by-step explanation:

step one:

The total bill was $45.

michelle pays 35% of the total bill

= 35/100*45

=0.35*45

=$15.75

lori pays 48% of the bill

= 48/100*45

=0.48*45

=$21.6

Therefore patti will pay

=45-15.75-21.6

=$7.65

3 0

3 years ago

Read 2 more answers

It cost $15 to enter apple farm and each apple is 0.25 writing equation in y=mx+b form to describe how much it'll cost one perso

postnew [5]

Answer:

Y=.25x+15

Step-by-step explanation:

Y is the total cost

15 is the set price

X is amount of apple that "will" be pick up ( Unknown apple that will be picked up so it is represented by X)

M is the price which is .25 per apple

6 0

3 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

5 0

3 years ago