How many liters of C3H6O are present in a sample weighing 25.6 grams?
1 answer:
Answer:
V = 0.0327 L.
Explanation:
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In this case, according to the given information, it turns out possible for us to calculate the liters of C3H6O by the definition of density. We can tell the density of this substance as that of acetone (0.784 g/mL) and therefore calculate the liters as shown below:
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<u>Answer:</u>
<u>For a:</u> The IUPAC name of the compound is N-ethylethaneamide.
<u>For b:</u> The IUPAC name of the compound is N,N-diethylmethaneamide.
<u>For c:</u> The IUPAC name of the compound is ethyl pentanoate
<u>Explanation:</u>
To name a compound, first look for the longest possible carbon chain.
- <u>For a:</u>
Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is , where R is an alkyl or aryl group.
In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'
Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N-ethylethaneamide.
- <u>For b:</u>
Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is , where R is an alkyl or aryl group.
In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'
Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'
Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.
- <u>For c:</u>
Esters are a kind of organic molecules having functional groups, where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.
These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.
In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'
Also, an ethyl group forms the alcoholic part.
Hence, the IUPAC name of the compound is ethyl pentanoate
