The balanced equation for
Ca(OH)2 + H3PO4→ Ca3(PO4)2 + H2O is
3 Ca(OH)2 +2 H3PO4→ Ca3(Po4)2 + 6 H2O
3 moles of Ca(OH)2 reacted with 2 moles of H3PO4 to form 1 mole of Ca3(PO4)2 and 6 moles of H2O
Fe2(SO4)3.3H2O = 56*2 + 3*(32+16*4)+3*(1*2+16) = 454 g/mol
Mol =m/M = 10.5/454 = 0.023 mol
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The rate of change of (g)=0.024M/s when the rate of change of is – 0.012 M/s.
<h3>What is the rate of reaction?</h3>
Reaction rate, in chemistry, is the speed at which a chemical reaction proceeds.
→
Rate = \frac{-dcs_2}{dt} =\frac{-do_2}{dt} =\frac{+dco_2}{dt} =\frac{1dso_2}{dt}
Given:
The rate of change of (g)=0.024M/s
Hence, the rate of change of (g)=0.024M/s
Learn more about the rate of change here:
brainly.com/question/13103052
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