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andre [41]
3 years ago
7

What are the spectator ions in Na+ + OH + H+ + Cl → H2O + Na+ + Cl?

Chemistry
2 answers:
Feliz [49]3 years ago
7 0
The answer would be h200 hope this helps
dexar [7]3 years ago
5 0

Answer:

h200

Explanation:

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WHATS THE AWNSER A b c oR D
IrinaK [193]

A or D most likly A tho

7 0
4 years ago
antimony(III) sulfide is reacted with excess iron. if 175.6 grams of pure antimony is produced what mass of antimony sulfide was
Ad libitum [116K]

Answer: -

The chemical formula of Antimony(III) sulfide = Sb₂S₃

Mass of Sb produced = 175.6 g

Molar mass of Sb = 121.76 g /mol

Number of moles of Sb = 175.6g / (121.76 g/mol)

= 1.44 mol

The balanced chemical equation for this reaction is

Sb₂S₃ + 3 Fe → 2 Sb + 3 FeS

From the chemical equation we see

2 mol of Sb is produced from 1 mol of Sb₂S₃

1.44 mol of Sb is produced from \frac{1 mol Sb2S3 x 1.44 mol Sb}{2 mol of Sb}

= 0.72 mol of Sb₂S₃

Molar mass of Sb₂S₃ = 2 x 121.76 + 32.06 x 3

= 339.7 g / mol

Mass of Sb₂S₃ = 0.72 mol x 339.7 g/ mol

= 244.58 g

= 244.6 g rounded off to 4 significant figures.

5 0
4 years ago
Which of the following is an example of an attempt to improve an environmental problem caused by chemicals
Leto [7]

what are the answer choices?

5 0
3 years ago
Read 2 more answers
When reacting calcium carbonate with hydrochloric acid, what action should be taken?
ExtremeBDS [4]
Calcium Carbonate + Hydrochloric Acid

CaCO₃ +HCl ⇒ CaCl₂ + H₂O + CO₂
6 0
4 years ago
The equilibrium constant kp at 427°c for the reaction n 2( g) 3h 2( g) 2nh 3( g) is 9. 4 × 10 –5. what is δ g° for the reaction
SashulF [63]

ΔG° for the reaction is 5.47kJ mol⁻¹.

The energy that a substance has available for utilization in a chemical reaction or transformation is known as the Gibbs free energy. Things frequently change into other things that have less Gibbs free energy. The Gibbs free energy change indicates whether a chemical reaction will take place spontaneously or not.

By using the formula;

ΔG° = −RTlnKp

Where,

R = 8.3Jk⁻¹mol⁻¹

T = Temperature = 427 + 273 = 700 K

Kp = 8×10⁻⁵(given)

Substituting the value, we get,

ΔG° = −8.3 × 700 × ln(23×10⁻⁵)

ΔG° = −8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       =  - 8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       = − 8.3 × 700 × (2.07−11.5)

       =5.47×10⁴Jmol¹

       =5.47kJ mol⁻¹

Therefore,  ΔG° for the reaction is 5.47kJ mol⁻¹.

Learn more about Gibbs free energy here:

brainly.com/question/13765848

#SPJ4

7 0
2 years ago
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