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Mkey [24]
3 years ago
14

A person walks in the following pattern: 3.1 km north, then 2.4 km west, and finally 5.2 km south. a) Sketch the vector diagram

that represents this motion. b) How far and in what direction would a bird fly in a straight line from the same starting point to the same final point?
Physics
1 answer:
zysi [14]3 years ago
3 0

Answer:

d = 3.19 km

direction is given as

\theta = 41.2 degree South of West

Explanation:

Part b)

displacement is given as

d_1 = 3.1 \hat j

d_2 = 2.4 \hat i

d_3 = 5.2(-\hat j)

now we will have

d = d_1 + d_2 + d_3

d = 2.4 \hat i + (3.1 - 5.2)\hat j

d = 2.4 \hat i - 2.1 \hat j

total displacement is given as

d = \sqrt{2.4^2 + 2.1^2}

d = 3.19 km

direction is given as

tan\theta = \frac{-2.1}{2.4}

\theta = 41.2 degree South of West

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Answer:

23376 days

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T^2\alpha R^3\\T^2=kR^3.......................(1)

where k is a constant.

From equation (1) we can deduce that the ratio of the square of the period of a planet to the cube of its mean distance from the sun is a constant.

\frac{T^2}{R^3}=k.......................(2)

Let the orbital period of the earth be T_e and its mean distance of from the sun be R_e.

Also let the orbital period of the planet be T_p and its mean distance from the sun be R_p.

Equation (2) therefore implies the following;

\frac{T_e^2}{R_e^3}=\frac{T_p^2}{R_p^3}....................(3)

We make the period of the planet T_p the subject of formula as follows;

T_p^2=\frac{T_e^2R_p^3}{R_e^3}\\T_p=\sqrt{\frac{T_e^2R_p^3}{R_e^3}\\}................(4)

But recall that from the problem stated, the mean distance of the planet from the sun is 16 times that of the earth, so therefore

R_p=16R_e...............(5)

Substituting equation (5) into (4), we obtain the following;

T_p=\sqrt{\frac{T_e^2(16R_e)^3}{(R_e^3}\\}\\T_p=\sqrt{\frac{T_e^24096R_e^3}{R_e^3}\\}

R_e^3 cancels out and we are left with the following;

T_p=\sqrt{4096T_e^2}\\T_p=64T_e..............(6)

Recall that the orbital period of the earth is about 365.25 days, hence;

T_p=64*365.25\\T_p=23376days

4 0
3 years ago
Write a short description of how the motion of the racers might change from the start of the race to the finish line
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3 years ago
An experiment is designed to investigate the relation between the pressure and temperature in a tank that has a constant volume
viva [34]

Answer:

3rd order polynomial

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The polynomial order that is best to use is the 3rd order polynomial, this is because using a 3rd order polynomial will produce a less variance and a low Bias

4 0
3 years ago
A spring of spring constant k is attached to a support at the bottom of a ramp that makes an angle θ with the horizontal. A bloc
Nikitich [7]

Answer:

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

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x(mgsin\theta+\mu_{k}mgcos\theta)=0.5kd^{2}

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5 0
3 years ago
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Marrrta [24]

Answer:

t = 6.09 seconds

Explanation:

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Hence, the time interval of the marble is 6.09 seconds.

6 0
3 years ago
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