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3 years ago

10

Two vectors, X and Y, form a right angle. Vector X is 48 inches long and vector Yis 14 inches long. The length of

1 answer:

Troyanec [42]3 years ago

6 0

48 inches go restaurant vector is 14 inches Long and right angle

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Which is the best predictor of the radioactive nature of an isotope?

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The Neutron-to-Proton Ratio. Hope this helps Sorry if it's wrong I'm a little rusty on Physics.

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3 years ago

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Objects that transmit some light and reflect/absorb the rest of the light, like stained glass, are

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3 years ago

Ubes have sides of equal lengths. What is the fastest way to measure the volume of a cube-shaped table?

Kryger [21]

The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three. Option B is correct.

<h3 /><h3>How do you calculate the volume of a cube?</h3>

Assume the side length of the cube under consideration is L units. The volume of the cube is then equal to L³ cubic units.

The volume of a cube is;

V = L³

Ubes have equal-length sides. The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three.

Hence option B is correct.

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2 years ago

an object tied to the end of the string moves in a circle . the force exerted by the string depends on the mass of the object it

otez555 [7]

Answer:Fc=mv^2/r

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3 years ago

A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800

Arada [10]

Explanation:

The given data is as follows.

m = 5000 kg, h = 800 km = $0.8 \times 10^{6} m$

$R_{e} = 6.37 \times 10^{6} m$ , r = R + h = $7.17 \times 10^{6} m$

$M_{e} = 5.98 \times 10^{24}$ kg, G = $6.67 \times 10^{-11} Nm^{2}/kg^{2}$

As we know that,

$\frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}$

v = $\sqrt{\frac{GM_{e}}{r^{2}}}$

And, it is known that formula to calculate angular velocity is as follows.

$\omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}$

v = $\sqrt{\frac{GM_{e}}{r^{3}}}$

= $\sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}$

= $1.0402 \times 10^{-3} rad/s$

Thus, we can conclude that speed of the satellite is $1.0402 \times 10^{-3} rad/s$ .

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3 years ago