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Andru [333]
3 years ago
13

A fishbowl has a circular opening with a diameter of 13 cm. The fishbowl sits upright on a table in a magnetic field of 0.00110

T that is directed downward. What is the flux through the glass of the bowl?
-1.5*10^-5 Wb
-4.5*10^-4 Wb
0.0 Wb
-5.8*10^-3 Wb
Physics
1 answer:
azamat3 years ago
5 0

Answer:

Did you ever get the answer?

Explanation:

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A bookcase has a base of 1 m long and 0.5 m wide. It has a mass of 300kg. Find the pressure it exerts on the floor in kPa.
Snezhnost [94]
1m*0.5m=0.5m^2\\
g=10\frac{m}{s^2}\\
300kg*10\frac{m}{s^2}=3000N\\
3000N--0.5m^2\\
\ \ x\ \ --\ 1\\
x=6000Pa=60kPa
4 0
3 years ago
The distance between slits in a double-slit experiment is decreased by a factor of 2. If the distance between fringes is small c
Elodia [21]

Answer:

the distance between adjacent fringes is increased by a factor o 2

Explanation:

To find how the distance between fringes is modified you can use the following formula for the calculation of the distance between fringes:

\Delta y=\frac{\lambda D}{d}

D: distance to the screen

d: distance between slits

λ: wavelength of the light

if d is decreased by a factor of 2, that is d'=1/2d, you have:

\Delta y'=\frac{\lambda D}{d'}=\frac{\lambda D}{(1/2)d}=2\Delta y

hence, the distance between adjacent fringes is increased by a factor o 2

4 0
3 years ago
Question 4 How much time does it take to walk 8 km north at a velocity of 3.8 km/h?​
IrinaVladis [17]

Given parameters:

Displacement = 8km

Velocity  = 3.8km/h

Unknown:

time  = ?

Solution:

Velocity is displacement divided by time.

  Velocity  = \frac{displacement}{time}  

      Displacement  = velocity x time

Input the parameters:

              8  = 3.8  x time

 Time  = \frac{8}{3.8}   = 2.1s

The time taken is 2.1s

6 0
3 years ago
What is the kind of energy that comes from movement?
Sergio [31]

Answer:

motion energy

Explanation:

motion wnergy is the sum of potential and kinetic energy

4 0
3 years ago
Read 2 more answers
A disk-shaped merry-go-round of radius 2.63 m and mass 152 kg rotates freely with an angular speed of 0.526 rev/s. A 51.7 kg per
zalisa [80]

 Explanation:

Given

radiusr=2.63 m

N=0.526 rev/s

\omega =3.30 rad/s

mass disc  M=152 kg

mass of person  m=51.7 kg

velocity of Person  v=2.76 m/s

moment of inertia  I=Mr^2

I=0.5\times 152\times 2.63^2=827.64 kg-m^2

Initial angular momentum

L_i=I\omega +mvr

L_i=827.64\times 3.30+51.7\times 2.76\times 2.63

L_i=2731.212+375.27=3106.48 Js

Final Moment inertia

I_f=0.5Mr^2+mr^2

I_f=(152\cdot 0.5+51.7)\cdot (2.63)^2=1185.243 kg-m^2

final angular momentum

L_f=I_f\omega _f

Conserving angular momentum

L_i=L_f

3106.48=1408.97\times \omega _f

\omega _f=2.62 rad/s

4 0
3 years ago
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