If an object travels 400 m in 253 s what is its speed in m/s?

Mathematics

2 answers:

Doss [256]3 years ago

6 0

Speed = distance / time

Speed = 400 / 253 

Speed = 1.58 m/s approx

Valentin [98]3 years ago

5 0

The answer would be 653 speed. Your welcome for the help.

You might be interested in

51/8 times 17/4and simplified

gayaneshka [121]

Answer:

27 3/32

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

In a class, 64 offers mathematics while 94 offers chemistry , How many will offer the both course?

Leokris [45]

Answer:

Step-by-step explanation:

94-64=30 will offer the same course because the chemistry offers ocerride the mathematics offers

7 0

3 years ago

if a class of 20 students 40% are boys. twenty-five percent often boys and 50% of the girls wear glasses. how many students wear

shtirl [24]

2 boys and 6 girls wear glasses, so 8 students wear glasses

7 0

2 years ago

Find the exact value of cos(arcsin(one fourth)). For full credit, explain your reasoning.

photoshop1234 [79]

We are asked to give the exact value of cos(arcsin(one fourth)). In this case, we shift first the setting to degrees since this involves angles. we determine first arc sin of one fourth equal to 14.48 degrees. then we take the cos of 14.48 degrees equal to 0.9682. Answer is 0.9682.

5 0

3 years ago

Factor 7(x − 3)2 − 4(x − 3) − 3 completely.

Nezavi [6.7K]

$7(x-3)^2-4(x-3)-3\\\\substitute\ t=x-3,\ then\ we\ have\\\\7t^2-4t-3\\\\a=7;\ b=-4;\ c=-3\\\\\Delta=b^2-4ac\\\\\Delta=(-4)^2-4\cdot7\cdot(-3)=16+84=100\\\\t_1=\dfrac{-b-\sqrt\Delta}{2a};\ t_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\t_1=\dfrac{-(-4)-10}{2\cdot7}=\dfrac{4-10}{14}=\dfrac{-6}{14}=-\dfrac{3}{7}\\\\t_2=\dfrac{-(-4)+10}{2\cdot7}=\dfrac{4+10}{14}=\dfrac{14}{14}=1\\\\7t^2-4t-3=7\left(t+\dfrac{3}{7}\right)(t-1)=(7t+3)(t-1)\\\\=(7(x-3)+3)(x-3-1)=(7x-21+3)(x-4)\\\\=\boxed{(7x-18)(x-4)}$

7 0

3 years ago