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NNADVOKAT [17]
4 years ago
15

A girl of weight 600N sits on a 3-leg chair which weighs 60N. Each chair leg presses the floor in a circle with a diameter of 5c

m. Find the average pressure exerted on the floor by each chair leg.
Physics
1 answer:
Daniel [21]4 years ago
8 0
Pressure = total force/total area

Total force = 660 Newton's

Total area:

Each leg contacts the floor with an area of πr^2=π(0.025m)^2=0.002m^2.

Total contact area for all 3 legs = 0.006 m^2.

Pressure = (660N) / (0.006 m^2)

= 110,000 N/m^2 = 110,000 Pascal's.

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2. 11.3 m/s

3. 12.5 m/s

Explanation:

<u>Question 1</u>

Pressure, P=hg\rho

Where h is the height that water is to reach, g is gravitational constant and \rho is the density, in this case, we assume \rho of pure water as 1000 Kg/m^3

Assuming g=10 m/s^{2}

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<u>Question 2</u>

Pressure can also be found by the formula

P=0.5v^{2}\rho where v is the velocity

Equating the new formula of pressure to the formula used in question 1 above

P=0.5v^{2}\rho=hg\rho

Notice that \rho is common hence

0.5v^{2}=hg

Making V the subject of the formula

v^{2}=2hg

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In this case, h=8-1.6=6.4m and taking g as 10 m/s^{2}

v=\sqrt 2*10*6.4=11.3137085  m/s

Rounding off to 1 decimal place

v=11.3 m/s

<u>Question 3</u>

As already illustrated

v=\sqrt 2hg

Taking g as 9.8 and h now is 8m

v=\sqrt 2*8*9.8

v=12.52198067

Rounding off to 1 decimal place

v=12.5 m/s

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y la verga de da en la cara

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