Answer:

Explanation:
According to Coulomb's law, the magnitude of the electric force between two equals charges (q) is given by:

Here k is the coulomb constant and d is the distance between the charges. For two electrons we have:

Answer:
200 N
Explanation:
Power = work / time
Work = force × distance
Therefore:
Power = force × distance / time
100 W = F × 10 m / 20 s
F = 200 N
He exerted 200 N.
Given: distance 1 d₁ = 40 m; distance 2 d₂ = 3.8 m g = -9.8 m/s²
Initial Velocity Vi = 0 Final Velocity of stone 2 is unknown = ?
Total distance dₓ = d₁ - d₂ = 40 m - 3.8 m = 36.2 m
Formula: a = Vf² - Vi²/2d derive for Final Velocity Vf
acceleration is now due to gravity, therefore a = g
Vf = √2gd Vf = √2(9.8 m/s²)(36.2 m)
Vf = 26.64 m/s
Reason: The second stone will still start from rest.