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mart [117]
2 years ago
12

How does the electric force between two charged particles change if the

Physics
1 answer:
posledela2 years ago
8 0

Answer:

D

Explanation:

If the distance is reduced by factor of 2, lets say the distance was 10cm

reducing by a factor of 2 will leave the distance at 5cm

so the electric force increases by a factor of 2

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An Olympic high jumper, with a mass of 82 kg, has a
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Answer:

I don't really know

Explanation:

I really wanted to help you, but then I realized i didnt know how to

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2 years ago
Once again, move the balloon to the right and let it go. Note how fast the balloon moves. Next, brush the balloon against the en
lilavasa [31]

Answer:

Yes. The balloon moves faster when it has more electrons and the sweater has fewer electrons

Explanation:

From Plato. Hope this helps!

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3 years ago
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A sample of 5.6 L of a gas is at a pressure of 1.5 atm. If the volume of the gas is compressed to 4.8 L, what will the new press
Effectus [21]

Answer:

1.75atm

Explanation:

According to Boyle's law, the pressure P of a fixed mass of gas is inversely proportional to it's volume V provided that the temperature remains constant.

P\alpha \frac{1}{V}\\hence\\PV=constant

This implies the following;

P_1V_1=P_2V_2=...=P_nV_n............(1) Provided temperature is kept constant.

Given;

P_1=1.5atm\\V_1=5.6L\\P_2=?\\V_2=4.8L

From equation (1), we can write;

P_1V_1=P_2V_2\\hence\\1.5*5.6=P_2*4.8\\\\P_2=\frac{1.5*5.6}{4.8}\\\\P_2=1.75atm

Since all the units are consistent, there is no need for conversion.

3 0
3 years ago
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a spring is stretched 20 cm by a 30.0 n force. determine the work done in stretching the spring from 0 to 40 cm?
Alekssandra [29.7K]

The work done when a spring is stretched from 0 to 40cm is 4J.

What is work done?

Work done is the magnitude of force multiplied by displacement of an object. It is also the amount of energy transferred to an object when work is done on that.

The work done on the spring to stretch to 40cm is,

F = kx

where F is force, k is force constant.

k = F / x = 10 N / 20 * 10^-2 m = 50 N/m

W = 0.5 * k * (x)^2

where W = work done, k = force constant.

W = 0.5 x 50 x (40 x 10^-2)^2 = 4 J.

Therefore, the work done on the spring when it is stretched to 40cm is 4J.

To learn more about work done click on the given link brainly.com/question/25573309

#SPJ4

3 0
1 year ago
Which statement accurately compares the weight of an object on these two planets
wel
"An object weighs about two times as much on Jupiter as on Neptune." Hope this helps :)
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3 years ago
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