C₀=2 mol/l
c₁=0.400 mol/l
v₁=100.0 ml = 0.1 l

c₁v₁=c₀v₀

v₀=c₁v₁/c₀
v(H₂O)=v₁-v₀

v₀=0.1*0.400/2=0.02 l = 20 ml
v(H₂O)=100 - 20 = 80 ml

It is necessary to mix 20 ml of the feed solution and 80 ml of water.

4 0

4 years ago

Read 2 more answers

Conversación de masa 3,6kg a g

Nikolay [14]

Explanation:

1kg = 1000g

3.6 kg = 3.6 × 100

3600g

7 0

3 years ago

Biphenyl, C12H10,C12H10, is a nonvolatile, nonionizing solute that is soluble in benzene, C6H6.C6H6. At 25 ∘C,25 ∘C, the vapor p

cestrela7 [59]

Answer:

Vapour pressure of solution is 78.151 torr

Explanation:

Molar mass of biphenyl = 154.21 g

Molar mass of benzene = 78.11 g

19.2 g biphenyl = (19.2/154.21) moles of biphenyl = 0.125 moles of biphenyl

33.7 g of benzene = (33.7/78.11) moles of benzene = 0.431 moles of benzene

Total number of moles = (0.125+0.431) moles = 0.556 moles

Mole fraction of benzene in solution = (0.431/0.556) = 0.775

According to Roults law, vapour pressure of solution made from non-volatile solute = $(mole fraction of solvent in solution)\times (vapour pressure of pure solvent)$