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Leviafan [203]
3 years ago
8

Not sure how to graph this

Mathematics
1 answer:
pychu [463]3 years ago
5 0
<h3>Answer: Graph a straight line through (0,-4) and (1,-8)</h3><h3>See diagram below</h3>

============================================================

Explanation:

Pick any number you want for x. I find x = 0 to be easiest. Plug this into the equation to get...

y = -4x-4

y = -4(0) - 4

y = 0-4

y = -4

This is the y intercept. The graph crosses the y axis at -4. So one point on this line is (0,-4) since x = 0 and y = -4 pair up together

---------------

Repeat for another x value, say x = 1

y = -4x-4

y = -4(1)-4

y = -4-4

y = -8

We have x = 1 and y = -8 pair up now. Therefore another point on this line is (1,-8)

We could repeat for other x values, but we have enough info to graph this straight line. We only need two points minimum to graph a straight line.

So from here all you need to do is plot (0,-4) and (1,-8). Then draw a straight line through the two points. The line extends infinitely out in both directions.

You could use any other two points you wanted. For me I just find it easiest to work with 0 and anything close to it.

-------

Note how starting at (0,-4) we have moved 4 units down and 1 unit to the right to arrive at (1,-8). The "4 units down, 1 unit to the right" comes exactly from the slope of -4 = -4/1

slope = rise/run = -4/1

rise = -4 means we move down 4

run = 1 means we move 1 to the right

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Answer:

She chose Option 2 which is a linear option, because it offers a smaller lose    

in value compared to option 1 which is an exponential option.

The final value for option 2=$32,800

Step-by-step explanation:

Option 1

New Zoomba for 60000 with a depreciation rat of 2%per month for 3 years

Exponential equation;

y=a(1-r)^t

where;

y=future value

a=initial value=60000

r=depreciation rate=2% per month

t=time interval=12×3=36 months

Replacing;

y=60000(1-2/100)^36

y=60000(0.98)^36=28,992.79

The value after 3 years=$28,992.79

Initial value-Final value=(60000-28992.79)=$31007.21

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(31007.21/60000)×100=51.68%

Option 2

New starfish for $40,000 with a depreciation of $200 per month for 3 years

Linear equation;

y=a-bt

where;

y=Future value

a=Initial value=$40,000

b=the depreciation amount per time interval=$200 per month for 3 years

t=time interval=(3×12)=36 months

Replacing;

y=40000-(200×36)

y=32,800

Final value=y=$32,800

Initial value-Final value=(40000-32800)=$7200

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(7200/40000)×100=18%

Option 1(51.68%)>Option 2(18%) therefor Option 1 loses value at a faster rate than Option 2

She chose Option 2 which is a linear option, because it offers a smaller lose    

in value compared to option 1 which is an exponential option

4 0
3 years ago
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