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Leviafan [203]
3 years ago
8

Not sure how to graph this

Mathematics
1 answer:
pychu [463]3 years ago
5 0
<h3>Answer: Graph a straight line through (0,-4) and (1,-8)</h3><h3>See diagram below</h3>

============================================================

Explanation:

Pick any number you want for x. I find x = 0 to be easiest. Plug this into the equation to get...

y = -4x-4

y = -4(0) - 4

y = 0-4

y = -4

This is the y intercept. The graph crosses the y axis at -4. So one point on this line is (0,-4) since x = 0 and y = -4 pair up together

---------------

Repeat for another x value, say x = 1

y = -4x-4

y = -4(1)-4

y = -4-4

y = -8

We have x = 1 and y = -8 pair up now. Therefore another point on this line is (1,-8)

We could repeat for other x values, but we have enough info to graph this straight line. We only need two points minimum to graph a straight line.

So from here all you need to do is plot (0,-4) and (1,-8). Then draw a straight line through the two points. The line extends infinitely out in both directions.

You could use any other two points you wanted. For me I just find it easiest to work with 0 and anything close to it.

-------

Note how starting at (0,-4) we have moved 4 units down and 1 unit to the right to arrive at (1,-8). The "4 units down, 1 unit to the right" comes exactly from the slope of -4 = -4/1

slope = rise/run = -4/1

rise = -4 means we move down 4

run = 1 means we move 1 to the right

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