Question

A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the nearest tenth. km/h What is the value of Ay? Round your answer to the nearest tenth. km/h

Answer 1

Answer:

$A_{x} =70.4 \frac{k}{h}$

$A_{y} =49.3\frac{km}{h}$

Explanation:

Hello

the helicopter is traveling at an angle of 35° to the ground, let this angle called a (α)

if A is the magnitude of the vector that forms an angle of 35, we have a rectangle triangle, where

h=86

α=35°

by definition

$cos\alpha =\frac{c.ady}{h} \\h*cos\alpha =A_{x}\\ \\A_{x}=86*cos (35)\\A_{x} =70.4 \frac{k}{h}$

now

$A_{y}\\\\ sin\alpha =\frac{catop}{h} \\h*sin(a)=A_{y}\\A_{y} =86*sin(35)\\A_{y} =49.3\frac{km}{h}$

Answer 2

First thing plot a right angle with angle of elevation of 35degrees as shown in figure then use SOHCAHTOA.

Ay/Helicopter = sin 35

Ay = 86 sin 35 = 36.8237

Ax/Helicopter = cos 35

Ax = 86 cos 35 = 77.7175

Note: I ignore the negative signs coz they signify direction