Answer:
Explanation:
Stiffness of spring k equal to 4 lb/ft.
Unstretched length of the spring L is equal to 0.5 feet.
Weight of the collar W is 15lb
Radius of curvature of curve guide is 1 feet
length of vertical rod is 1.5 feet
Initial speed of collar when released from rest at A is 0 feet per seconds
use the energy conservation equation

Estimate the potential energy , component as position B as below

Estimate the kinetic energy , component as position A as below

Estimate the kinetic energy , component as position B as below

Substitute 20.5lb- ft for 
0.5lb-ft for 
0lb -ft for 


= 16.05ft/sec
Answer:
It depends on 2 factors
the nature of the materials
the normal force.
Explanation:
It depends on 2 factors
the nature of the materials that are in friction and the treatment that they have followed. This factor is expressed by a numerical value called the coefficient of friction or friction.
the force exerted by one body on the other, that is, the normal force.
Medulla is the answer to this qestion
Answer: SG = 2.67
Specific gravity of the sand is 2.67
Explanation:
Specific gravity = density of material/density of water
Given;
Mass of sand m = 100g
Volume of sand = volume of water displaced
Vs = 537.5cm^3 - 500 cm^3
Vs = 37.5cm^3
Density of sand = m/Vs = 100g/37.5 cm^3
Ds = 2.67g/cm^3
Density of water Dw = 1.00 g/cm^3
Therefore, the specific gravity of sand is
SG = Ds/Dw
SG = (2.67g/cm^3)/(1.00g/cm^3)
SG = 2.67
Specific gravity of the sand is 2.67