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1 answer:

ASHA 777 [7]3 years ago

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240 +14 = X

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A Carnot engine operates with an efficiency of 26.0% when the temperature of its cold reservoir is 281 K. Assuming that the temp

VLD [36.1K]

Answer:

The temperature of cold reservoir should be 246.818 K for efficiency of 35%

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In first case we have given efficiency of Carnot engine = 26 % = 0.26

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$\eta =1-\frac{T_L}{T_H}$

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So $0.35=1-\frac{T_L}{379.72}$

$T_L=246.818K$

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4 years ago