Y-axis symmetry=(r, theta)=(-r,theta)
-5-5cos(theta)=r
-r=5+5cos(theta)
no y-axis symmetry
x-axis symmetry=(r,theta)=(r,-theta)
cosine is an even function, so yes it is symmetric around x-axis
origin symmetry=(r,theta)=(-r,theta) or (r, theta+pi)
no, as there is no y-axis symmetry
Answer:
(1/2,-5/2)
Step-by-step explanation:
![\frac{ - 3 + 4 }{2} = \frac{1}{2} \\ \frac{ - 4 + - 1}{2} = \frac{ - 5}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%203%20%2B%204%20%7D%7B2%7D%20%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%5C%5C%20%20%20%5Cfrac%7B%20-%204%20%2B%20%20-%201%7D%7B2%7D%20%20%3D%20%20%20%5Cfrac%7B%20-%205%7D%7B2%7D%20%20)
×=y/3-z/3+3 thats the x value in this equation
Answer:
DCB ~ RST
JKL ~ JTU
Step-by-step explanation:
Answer:
650
Step-by-step explanation: