Question

Help solve these two problems im having trouble trying to start these problems?​

Answer 1

Answer:

25.  Approximately 8.1 meters

26. North 1.31 km, and East 2.81 km

Explanation:

25.

Notice that the displacements: 6 meters east and 5.4 south create the legs of a right angle triangle. The hypotenuse of that triangle will be the distance (d) needed to cover in order to get the ball in the hole in one putt. That is:

$d=\sqrt{6^2+5.4^2} =\sqrt{65.16} \approx 8.072\,\,\,m$

which can be rounded to 8.1 m.

26.

Notice that the 3.1 km at an angle of 25 degrees north of east, is the hypotenuse of a right angle triangle that has for legs the east and north components of that distance.

We can find the leg corresponding to the east displacement using the cosine function (that relates adjacent side with hypotenuse):

$east\,\, comp=3.1 * cos(25^o)\approx 2.809\,\,km$

and we can calculate the north component using the sine function that relates the opposite side to the angle with the hypotenuse.

$north\,\,component = 3.1 * sin(25^o) \approx 1.31 \,\,km$