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3 years ago

Help solve these two problems im having trouble trying to start these problems?

Physics

1 answer:

belka [17]3 years ago

6 0

Answer:

25. Approximately 8.1 meters

26. North 1.31 km, and East 2.81 km

Explanation:

25.

Notice that the displacements: 6 meters east and 5.4 south create the legs of a right angle triangle. The hypotenuse of that triangle will be the distance (d) needed to cover in order to get the ball in the hole in one putt. That is:

$d=\sqrt{6^2+5.4^2} =\sqrt{65.16} \approx 8.072\,\,\,m$

which can be rounded to 8.1 m.

26.

Notice that the 3.1 km at an angle of 25 degrees north of east, is the hypotenuse of a right angle triangle that has for legs the east and north components of that distance.

We can find the leg corresponding to the east displacement using the cosine function (that relates adjacent side with hypotenuse):

$east\,\, comp=3.1 * cos(25^o)\approx 2.809\,\,km$

and we can calculate the north component using the sine function that relates the opposite side to the angle with the hypotenuse.

$north\,\,component = 3.1 * sin(25^o) \approx 1.31 \,\,km$

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(i) a force of 35.0 n is required to start a 6.0-kg box moving across a horizontal concrete floor, (a) what is the coefficient o

Serjik [45]

a. The force applied would be equal to the frictional force.

F = us Fn

where, F = applied force = 35 N, us = coeff of static friction, Fn = normal force = weight

35 N = us * (6 kg * 9.81 m/s^2)

us = 0.595

b. The force applied would now be the sum of the frictional force and force due to acceleration

F = uk Fn + m a

where, uk = coeff of kinetic friction

35 N = uk * (6 kg * 9.81 m/s^2) + (6kg * 0.60 m/s^2)

uk = 0.533

4 0

3 years ago

What will be the density of the air if the radius of the cylinder is halved while the length is unchanged?

pickupchik [31]

If the radius of the cylinder is halved and length is kept unchanged then the density of air inside the cylinder will increase.

As it can be said that density is inversely proportion to the square of the radius.

Density of Cylinder

Density is the ratio of mass to volume.

The formula for density is: ρ= m/v.

The formula for the Mean Density of a cylinder is:

ρ= m/ (π•r²•h)

where:

ρ is the density of the cylinder

m is the mass of the cylinder

h is the height of the cylinder

So, with increase in radius the of the cylinder there is decrease in the density of cylinder.

And on decreasing the radius of the cylinder there is increase in the density of the cylinder.

As it can be said that density is inversely proportion to the square of the radius.

To learn more about Density Of Cylinder

brainly.com/question/19245086

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8 0

2 years ago

The initial momentum and the vertical and horizontal component

tamaranim1 [39]

Momentum = mass * velocity

p = mv

p = 1.5 kg * 40 ms^-1

p = 60 kgm/s

To find components of a vector:

px = p * cos(theta)
px = 60 * cos(30)
px = 51.96 = 52 (rounded to two significant digits)

py = p * sin(theta)
py = 60 * sin(30)
py = 30

He initial momentum is 60kgm/s
The horizontal component is 52 kgm/s
The vertical component is 30 kgm/s

8 0

3 years ago

A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t

marishachu [46]

Answer:

The impact occured at a distance of 2478.585 meters from the person.

Explanation:

(After some research on web, we conclude that problem is not incomplete) The element "Part A" may lead to the false idea that question is incomplete. Correct form is presented below:

<em>A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 6.4 seconds apart. How far away did the impact occur? (Sound speed in the air: 343 meters per second, sound speed in concrete: 3000 meters per second)</em>

Sound is a manifestation of mechanical waves, which needs a medium to propagate themselves. Depending on the material, sound will take more or less time to travel a given distance. From statement, we know this time difference between air and concrete ( $\Delta t$ ), in seconds:

$\Delta t = t_{A}-t_{C}$ (1)

Where:

$t_{C}$ - Time spent by the sound in concrete, in seconds.

$t_{A}$ - Time spent by the sound in the air, in seconds.

By suposing that sound travels the same distance and at constant speed in both materials, we have the following expression:

$\Delta t = \frac{x}{v_{A}}-\frac{x}{v_{C}}$

$\Delta t = x\cdot \left(\frac{1}{v_{A}}-\frac{1}{v_{C}} \right)$

$x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}} }$ (2)

Where:

$v_{C}$ - Speed of the sound in concrete, in meters per second.

$v_{A}$ - Speed of the sound in the air, in meters per second.

$x$ - Distance traveled by the sound, in meters.

If we know that $\Delta t = 6.4\,s$ , $v_{C} = 3000\,\frac{m}{s}$ and $v_{A} = 343\,\frac{m}{s}$ , then the distance travelled by the sound is:

$x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}} }$

$x = 2478.585\,m$

The impact occured at a distance of 2478.585 meters from the person.

7 0

3 years ago

What is the magnitude of the kinetic frictional force

Sophie [7]

Answer:

Magnitude of kinetic force is the product of the normal force and the coefficient of kinetic friction.

Explanation:

The kinetic frictional force is the force which is experienced in the moving surfaces of bodies.The magnitude of the force is affected by the coefficient of kinetic friction between the material of two bodies in contact. Mathematically, it is expressed as;

Fk=μk*η

where;

Fk=force of kinetic friction
μk=coefficient of kinetic friction
η=normal force

3 0

4 years ago

Help solve these two problems im having trouble trying to start these problems?​

Help solve these two problems im having trouble trying to start these problems?