Which situation describes the best example of rotational motion?

A 3 kg block is released from rest to slide down a ramp with friction. The length that the block slides is 2 meters and the angl

Arte-miy333 [17]

Answer:

(a). The acceleration is 3.20 m/s².

(b). The amount of work done by each force is 19.2 J.

(c). The total work done on the block is 19.2 J.

(d). The final speed of the block is 6.26 m/s.

Explanation:

Given that,

Mass of block = 3 kg

Distance = 2 m

Angle = 30°

Coefficient of kinetic friction = 0.20

(a). We need to calculate the acceleration

Using balance equation of force

$N = mg\co\theta$

$mg\sin\theta-f_{k}=ma$

$a = g\sin\theta-\mu g\cos30$

Put the value into the formula

$a=g(\sin30-0.20\cos30)$

$a=9.8(\dfrac{1}{2}-0.20\times\dfrac{\sqrt{3}}{2})$

$a=3.20\ m/s^2$

The acceleration is 3.20 m/s².

(b). We need to calculate the amount of work done by each force

Using formula of work done

Normal force is

$N = mg\cos30$

So due to this the net force is zero then the no work done by reaction force.

By another force,

$W= F\times d$

$W=ma\times d$

Put the value into the formula

$W= 3\times3.20\times2$

$W=19.2\ J$

The amount of work done by each force is 19.2 J.

(c). We need to calculate the total work done on the block

The total work done on the block is 19.2 J.

(d). We need to calculate the final speed of the block

Using equation of motion

$v^2=u^2+2gs$

Put the value into the formula

$v^2=0+2\times9.8\times2$

$v=\sqrt{2\times9.8\times2}$

$v=6.26\ m/s$

The final speed of the block is 6.26 m/s.

Hence, This is the required solution.

4 0

3 years ago

The magnetic field due to a utility wire is 0.10 mT when you are at a distance of 10 meters from it. What current (in Amperes) f

ale4655 [162]

Answer:

I = 5000 A

Explanation:

We will use Ampere's Law to calculate the current:

$B = \frac{\mu I}{2\pi r}\\\\$

where,

B = Magnetic Field Strength = 0.1 mT = 1 x 10⁻⁴ T

μ = Permeability of Free Space = 4π x 10⁻⁷ N/A²

I = Current = ?

r = radius = 10 m

Therefore,

$1\ x\ 10^{-4}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(I)}{2\pi(10\ m)}\\\\I = \frac{(1\ x\ 10^{-4}\ T)(2\pi (10\ m))}{4\pi\ x\ 10^{-7}\ N/A^2}$

I = 5000 A

4 0

3 years ago

A 620 kg moose is standing in the middle of a train track. A 10,000 kg train moving at 10 m/s is unable to stop and the moose en

ddd [48]

Answer:

This is an example of Inelastic colission

Explanation:

Step one:

given:

mass of moose m1 = 620 kg

mass of train m2= 10,000kg

Initial velocity of moose u1= 0 m/s

Initial velocity of train v1 = 10m/s

combined velocity of the system is given as v

Applying the conservation of momentum equation we have

m1u1+ m2u1= (m1+m2)V

substitutting we have

620*0+10000*10= (620+10000)V

100000= 10620V

divide both sides by 10620

V = 100000/10620

V=9.41m/s

The velocity of the moose after impact is 9.41m/s

4 0

3 years ago

Convert 6.95×105 cal to joules. recall that 1 cal=duncan takes a break from studying and goes to the gym to swim laps. if swimmi

quester [9]

For this problem, let's use the approach of dimensional analysis. This technique is done by cancelling out like units that appear both on the numerator and the denominator side. As a result, this technique will let you know that your final answer conforms to what parameter is asked. In this case, the final answer should be in kJ. We use the conversion: 1000 cal = 4.184 kJ The solution is as follows:

6.95×10⁵ cal * 4.184 kJ/1000 cal = 2,907.88 kJ

3 0

4 years ago

1)If I'm on an elevator that breaks loose and plummets down the shaft, can I avoid harm by jumping at the last second?

umka2103 [35]

Answer and Explanation:

1) If you were to jump at the last second, you would decrease the impact velocity by 7 mph. This is because most humans have a maximum jump velocity of 7 mph. You may still get hurt, but the damage would be significantly less than if you were to not jump.

2) Bathroom mats are made of fabrics, and fabrics absorb the moisture in the air. If you were to take a shower at any temperature, the fabric will soak up the moisture in the air, so when you touch it, it doesn't feel cold.

The tile floor, however, isn't able to store the moisture into itself. The temperature of the tile will be less than the temperature of your feet.

#teamtrees #PAW (Plant And Water)

I hope this helps!

5 0

3 years ago