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mixas84 [53]
3 years ago
11

An airplane flying at 115 m/s due east makes a gradual turn following a circular path to fly south. The turn takes 15 seconds to

complete. a. What is the radius of the curve that the plane follows in making the turn? b. What is the magnitude of the centripetal acceleration during the turn?
Physics
1 answer:
bulgar [2K]3 years ago
3 0

To solve this exercise it is necessary to apply the concepts related to Centripetal and Perimeter acceleration of a circle.

The perimeter of a circle is defined by

P = 2\pi r

Where,

r= radius

While centripetal acceleration is defined by

a=\frac{v^2}{r}

Where,

v= velocity

r= radius

PART A)

The distance of a body can be defined based on the speed and the time traveled, that is

x = v*t

For our values the distance is equal to

x = 15*115=1725m

The plane when going to make the turn from east to south makes a quarter of the circumference that is

\frac{P}{4} = \frac{2\pi r}{4}

The same route you take is the distance traveled, that is

x = \frac{P}{4}

x = \frac{2\pi r}{4}

1725 = \frac{2\pi r}{4}

r = 1098.17m

PART B)

With the radius is possible calculate he centripetal acceleration,

a = \frac{v^2}{r}

a = \frac{115^2}{1098.17}

a = 12.04m/s^2

Therefore the radius of the curva that the plane follows in making the turn is 1098.17m with a centripetal acceleration of 12.04m/s^2

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insens350 [35]

Answer:

24.531 m

Explanation:

t = Time taken = 1.7 s

u = Initial velocity = 6.1 m/s

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Equation of motion

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=6.1\times 1.7+\dfrac{1}{2}\times 9.8\times 1.7^2\\\Rightarrow s=24.531\ m

The initial height of the rock above the ground is 24.531 m

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3 years ago
When a falling object reaches terminal velocity, the net force acting on it is
dexar [7]
Pretty sure that it is 0.
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This is a velocity versus time graph of a car starting from rest. If the area under the line is 10 meters, what is the correspon
adelina 88 [10]

So the area under a velocity time graph is distance or displacement, if you have done calculus yet you will understand that if you take the integral of a velocity function then you end up with displacement. Thats for later understanding however.

So this appears to be a right triangle so we can find the area of a triangle as:

0.5bh = A

Since our area is 10 meters lets alter our formula a bit to fit the situation:

Our base here is time and our height is velocity so:

0.5tv = Δx

So we can read off the graph that our velocity at the end, or our final velocity appears to be near 2.0 m/s

So we have v, and Δx so lets isolate for time by dividing by v and 0.5

t = Δx / 0.5v

Now lets plug all that in:

t = 10 / 0.5(2)

t = 10 seconds

Hope this helped!

8 0
3 years ago
An elevator weighing 2,200 lbs is raised one story in 20 seconds. If the distance between stories is 10 feet, the power is devel
kaheart [24]

Answer: 1100 ft lb/s and 2 H.P

Explanation:

To calculate for the power developed in the elevator motor in ft.lb/s, we multiply the distance and the weight of the elevator and divide the product by the time.

                      Power = (10 ft)(2200 lb) / 20 s = 1100 ft.lb/s

Next, convert the calculated value to HP. 

                             1100 ft.lb/s x (1 HP/ 550 ft.lb/s) = 2 HP

hope this helps please give brainliest!

5 0
3 years ago
A diesel engine does not use spark plugs to ignite the fuel and air in the cylinders. Instead, the temperature required to ignit
Klio2033 [76]

Answer:

Compression ratio = 24.42

Explanation:

From Thermodynamic,

Adiabatic Equation ⇒ TV^{γ-1} = Constant.

⇒T₁V₁^{γ-1}  = T₂V₂^{γ-1} ..................(1)

Where T₁= initial Temperature, V₁ = Initial Volume, T₂ = final Temperature, V₂ = Final Volume.

Given:  T₁= 18°C we convert to  Kelvin(K) by adding 273.

∴      T₁= 18°C + 273 = 291K

        T₂ = 733° C  also,we convert to  Kelvin(K) by adding 273

 ∴      T₂ = 733° C +273 =1046K

          γ = 7/5

 ∴ Rearranging equation(1), we have

    (T₁/T₂) = (V₂/V₁)^{γ-1}................(2)

also rearranging equation(2) we have

   (V₁/V₂)^{γ-1} = (T₂/T₁).

Where (V₁/V₂) = Compression ratio.

∴ (V₁/V₂)^{(7/5)-1} =( 1046/291)

simplifying the index in the equation

I.e (7/5)-1 = (7-5 )/5 = 2/5.

(V₁/V₂)^2/5 =(1046/291)^2/5

Multiplying the power on both side of the equation by 5/2.

∴(V₁/V₂)^(2/5)×(5/2) = (1046/291)^(5/2)

⇒ V₁/V₂= (1046/291)^2.5=( 3.59)^2.5

    V₁/V₂ = 24.42.

∴ Compression ratio = 24.42

7 0
3 years ago
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