Answer
0.001339 liter
Explanation:
It is given that radius = 4 cm =0.04 m
volume of sphere 
It is given that hose delivers five liters per minute
So the water flows through sphere per minute is given by 5×2.674×
=0.001339 liters
C = 3 uf = 3 × 10^(-6) f
v = 6volts
Q = C.v
= <span>3 × 10^(-6) </span>× 6
= 18 × 10^(-6)
= 1.8 = 10^(-5)
This question is incomplete, the complete question is;
The Figure shows a container that is sealed at the top by a moveable piston, Inside the container is an ideal gas at 1.00 atm. 20.0°C and 1.00 L.
"What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant?"
Answer:
the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant
Explanation:
Given that;
P₁ = 1.00 atm
P₂ = ?
V₁ = 1 L
V₂ = 1.60 L
the temperature of the gas is kept constant
we know that;
P₁V₁ = P₂V₂
so we substitute
1 × 1 = P₂ × 1.60
P₂ = 1 / 1.60
P₂ = 0.625 atm
Therefore the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant
It will tend to follow a trajectory path. When a projectile is being flung or flown away by a certain type of force, the trajectory is what it follows through the means of both force and function of time itself. It's also called as flight path.
