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Semenov [28]
3 years ago
15

A positive charge is moved from point a to point b along an equipotential surface. How much work is performed or required in mov

ing the charge?
Physics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

The work done is zero

Explanation:

No work is performed or required in moving the positive charge from point A to point B

You might be interested in
Flowchart symbols
MArishka [77]

Answer:

Option (A)

Explanation:

A flowchart can be described as a representation of a process or an algorithm in a sequential manner (stepwise) in the form of diagrams. These steps are made of symbols that are connected to one another with the help of arrows. These arrows are used to show the direction of the process.  

There are mainly four symbols that are used to describe a flow chart, which includes-

  • Oval or Pill Shape- This type of symbol is used to depict the start or the end of a process.
  • Rectangle Shape- This type of symbols is used to describe the process .
  • Diamond Shape- This type of symbol is used to represent decision s.
  • Parallelogram- This type of symbol is used for the representation of an input or an output.

Thus, the correct answer is option (A).

5 0
3 years ago
Match the term with its description.
Mrac [35]

A=Ion

B=pH

C=Acid

D=Alkaline

6 0
3 years ago
What is the mass of metal if it has a density of 12.459 hg/cm^3 and displaces 28.7cm^3 of water ​
natima [27]

Answer:

357.6g

Explanation:

Given parameters:

Density  = 12.459g/cm³

Volume of metal  = 28.7cm³

Unknown:

Mass of metal = ?

Solution:

The density of a substance is its mass per unit volume.

To find the mass;

     Mass of metal  = density x volume

Now insert the parameters and solve;

    Mass of metal  = 12.459 x 28.7  = 357.6g

7 0
3 years ago
3. Una cuerda de guitarra tiene 60 cm de longitud y una masa de 0.05 kg de masa. Si se tensiona mediante una fuerza de 20 N. La
jok3333 [9.3K]

Answer:

f1 = 12.90 Hz

Explanation:

To calculate the first harmonic frequency you use the following formula for n = 1:

f_n=\frac{n}{2L}\sqrt{\frac{T}{M/L}}

f_1=\frac{1}{2L}\sqrt{\frac{T}{M/L}}    ( 1 )

It is necessary that the unist are in meters, then you have:

L: length of the string = 60cm = 0.6m

M: mass of the string = 0.05kg

T: tension on the string = 20 N

you replace the values of L, M and T in the expression (1) for getting f1:

f_1=\frac{1}{2(0.6m)}\sqrt{\frac{20N}{0.05kg/0.6m}}=12.90\ Hz

Hence, the first harmonic has a frequency of 12.90 Hz

4 0
3 years ago
Marys airplane trip took 5.8 hours for one-half of that time, the airplane flew at a constant speed of 640 miles per hour and fo
Olenka [21]
Distance is speed x time.  Half of the trip is 5.8/2 = 2.9hrs.
640 x 2.9 = 1856mi
580 x 2.9 = 1682mi
1856mi+1682mi=3538mi.

You could also calculate her average speed.  This is easy since it was divided in two equal time slices.  Average Speed = (640+580)/2 = 610mi/hr
Now 610mi/hr x 5.8hrs = 3538mi
7 0
3 years ago
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