Answer:
F₁ = 4.29 x 10⁵ N
Explanation:
The total force required to move the freight train with the given acceleration is given by the following formula:
F = ma + f
where,
F = Total Force Required from both engines = ?
m = equivalent mass of system = 2(8 x 10⁵ kg) + 5.5 x 10⁵ kg = 21.5 x 10⁵ kg
a = required acceleration = 5 x 10⁻² m/s²
f = force of friction = 7.5 x 10⁵ N
Therefore,
F = (21.5 x 10⁵ kg)(0.05 m/s²) + 7.5 x 10⁵ N
F = 8.575 x 10⁵ N
Now, for identical forces in each engine can be given as:
Force exerted by each engine = F₁ = F/2
F₁ = 8.575 x 10⁵ N/2
<u>F₁ = 4.29 x 10⁵ N</u>
Answer:
4.454 N.
Explanation:
The force on a current carrying conductor in a magnetic field is given as,
F = BILsinФ................... Equation 1
Where F = magnetic Force, B = magnetic Field, I = current, L = Length of the wire, Ф = The angle between the conductor and the Field.
Given: B = 0.289 T, I = 6.91 A, L = 6.7 m, Ф = 19°
Substitute into equation 1
F = 0.289(6.91)(6.7)sin19
F = 0.289×6.91×6.7×0.33
F = 4.454 N.
Hence the magnetic force = 4.454 N.
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Below are the choices that can be found from other source:
<span>A. The total momentum of the system is conserved.
</span><span>B. The total momentum of the system is not conserved.
</span><span>C. The total momentum of the system is zero.
</span><span>D. The total momentum of the system is negative.
</span>
The answer is A.
-3.33 m/s^2
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