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3 years ago

Select the correct answer. Which type of energy is thermal energy a form of

1 answer:

7 0

Kinetic energy. thermal energy (a low form of energy ) is a form of kinetic energy as it is produced as a result of motion of particles either if they vibrate at their position or they move along longer paths. Motion produces friction or resistance which leads to excitation and thus the heat is produced. The higher the motion of the particles, the higher would be the thermal energy.

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Some metals have a molecular structure that makes them good conductors. Explain how understanding this relationship can help eng

erastova [34]

Answer:

Explained below.

Explanation:

Conductors can be defined as materials that permit electricity to flow through them easily.

Now, metals have a molecular structure that makes them good conductors because electrons in the atoms of these conductors tend to move freely from one atom to the other. So a majority of metals make good conductors because these metals tend to hold their electrons loosely. In short, it can help engineers make powerful batteries because then it means that they are capable of giving much more electrical energy since nowadays, advanced batteries make use of ion charges for the batteries.

7 0

3 years ago

Two 5.0-g aluminum foil balls hang from 1.0-m-long threads that are suspended from the same point at the top. The charge on each

Allisa [31]

Answer: F=0.075N

Explanation:

T*cos(θ) = mg=0.005X9.8

T*cos(θ)=0.049N

T = 0.049/cosθ

F = k*q1*q2 / r2

F = 8.9875 * 10^9 * q1*q2 / r^2 q1

F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2

F=0.2246875/r^2

r= 2Lsinθ = 2 x 1 x sinθ =2sinθ

Kindly check the attached for further solution

5 0

3 years ago

A river 500 ft wide flows with a speed of 8 ft/s with respect to the earth. A woman swims with a speed of 4 ft/s with respect to

White raven [17]

Answer:

1) $\Delta s=1000\ ft$

2) $\Delta s'=998.11\ ft.s^{-1}$

3) $t\approx125\ s$

$t'\approx463.733\ s$

Explanation:

Given:

width of river, $w=500\ ft$

speed of stream with respect to the ground, $v_s=8\ ft.s^{-1}$

speed of the swimmer with respect to water, $v=4\ ft.s^{-1}$

Now the resultant of the two velocities perpendicular to each other:

$v_r=\sqrt{v^2+v_s^2}$

$v_r=\sqrt{4^2+8^2}$

$v_r=8.9442\ ft.s^{-1}$

Now the angle of the resultant velocity form the vertical:

$\tan\beta=\frac{v_s}{v}$

$\tan\beta=\frac{8}{4}$

$\beta=63.43^{\circ}$

Now the distance swam by the swimmer in this direction be d.

so,

$d.\cos\beta=w$

$d\times \cos\ 63.43=500$

$d=1118.034\ ft$

Now the distance swept downward:

$\Delta s=\sqrt{d^2-w^2}$

$\Delta s=\sqrt{1118.034^2-500^2}$

$\Delta s=1000\ ft$

On swimming 37° upstream:

The velocity component of stream cancelled by the swimmer:

$v'=v.\cos37$

$v'=4\times \cos37$

$v'=3.1945\ ft.s^{-1}$

Now the net effective speed of stream sweeping the swimmer:

$v_n=v_s-v'$

$v_n=8-3.1945$

$v_n=4.8055\ ft.s^{-1}$

The component of swimmer's velocity heading directly towards the opposite bank:

$v'_r=v.\sin37$

$v'_r=4\sin37$

$v'_r=2.4073\ ft.s^{-1}$

Now the angle of the resultant velocity of the swimmer from the normal to the stream:

$\tan\phi=\frac{v_n}{v'_r}$

$\tan\phi=\frac{4.8055}{2.4073}$

$\phi=63.39^{\circ}$

Now let the distance swam in this direction be d'.

$d'\times \cos\phi=w$

$d'=\frac{500}{\cos63.39}$

$d'=1116.344\ ft$

Now the distance swept downstream:

$\Delta s'=\sqrt{d'^2-w^2}$

$\Delta s'=\sqrt{1116.344^2-500^2}$

$\Delta s'=998.11\ ft.s^{-1}$

Time taken in crossing the rive in case 1:

$t=\frac{d}{v_r}$

$t=\frac{1118.034}{8.9442}$

$t\approx125\ s$

Time taken in crossing the rive in case 2:

$t'=\frac{d'}{v'_r}$

$t'=\frac{1116.344}{2.4073}$

$t'\approx463.733\ s$

7 0

4 years ago

Which graph best represents the relationship between the conductivity and the temperature of semiconductors ?

Volgvan

Answer: I think the answer is B

Explanation:

6 0

3 years ago

Read 2 more answers

Glider A of mass 2.5 kg moves with speed 1.7 m/s on a horizontal rail without friction. It collides elastically with glider B of

omeli [17]

Answer:

The speed of glider A after the collision is 0 m/s

Explanation:

Hi there!

The two gliders collide elastically. That means that the kinetic energy and momentum of the system are conserved, i.e., they remain constant before and after the collision.

The momentum is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass.

v = velocity.

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Where:

KE = kinetic energy.

m = mass.

v = velocity.

The momentum of the system is the sum of the momentum of each glider.

be:

mA = mass of glider A

mB = mass of glider B

vA = velocity of glider A before the collision.

vB = velocity of glider B before the collision.

vA´= velocity of glider A after the collision.

vB´= velocity of glider B after the collision.

The momentum of the system will be:

mA · vA + mB · vB = mA · vA´ + mB · vB´

Replacing with the given data:

2.5 kg · 1.7 m/s + 2.5 kg · 0 m/s = 2.5 kg · vA´ + 2.5 kg · vB´

divide both sides of the equation by 2.5 kg:

1.7 m/s = vA´ + vB´

1.7 m/s - vA´ = vB´

Using the conservation of the kinetic energy of the system we can find vA´:

1/2 · mA · vA² + 1/2 · mB · vB² = 1/2 · mA · vA´² + 1/2 · mB · (1.7 m/s - vA´)²

Let´s replace with the given data:

1/2 · 2.5 kg · (1.7 m/s)² + 0 = 1/2 · 2.5 kg · vA´² + 1/2 · 2.5 kg · (1.7 m/s - vA´)²

divide both sides of the equation by (1/2 · 2.5 kg):

(1.7 m/s)² = vA´² + (1.7 m/s - vA´)²

(1.7 m/s)² = vA´² + (1.7 m/s)² - 2· 1.7 m/s · vA´ + vA´²

0 = 2vA´² - 2· 1.7 m/s · vA´

0 = 2vA´(vA´ - 1.7 m/s)

vA´ = 0

vA´ - 1.7 m/s = 0

vA´ = 1.7 m/s

Since the velocity of the glider A after the collision can´t be the same as before the collision, the velocity of glider A after the collision is 0 m/s.

4 0

3 years ago