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Firdavs [7]
4 years ago
7

According to Newton's first law, if an object is slowing down, what must be happening? A. No forces are acting on it. B. A singl

e force is acting on it. C. Balanced forces are acting on it. D. Unbalanced forces are acting on it.
Physics
1 answer:
Gnom [1K]4 years ago
6 0

The correct answer would be D. Unbalanced forces are acting on it.

Hope that helps u!! :)

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Una soga, en la que en un instante dado existen 163 N de tensión, sube verticalmente una cubeta de 12.0 kg. ¿Cuál es la acelerac
Yanka [14]

Answer:

a = 3.776\,\frac{m}{s^{2}} (hacia arriba).

Explanation:

La dirección y magnitud de la aceleración se determina a partir de la siguiente ecuación de equilibrio:

\Sigma F = T - m\cdot g = m\cdot a

La expresión de la aceleración es:

a = \frac{T}{m} - g

a = \frac{163\,N}{12\,kg}-9.807\,\frac{m}{s^{2}}

a = 3.776\,\frac{m}{s^{2}}

La cubeta es acelerada hacia arriba.

6 0
4 years ago
Why are there so few top level consumers in massachusetts?
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3 years ago
astone is thrown upwards with an initial velocity of 25m/s atan angle of 30 to the ground.what is the work out the stones horiza
vovikov84 [41]

Answer:

<u>Range</u><u> </u><u>is</u><u> </u><u>6</u><u>2</u><u>.</u><u>5</u><u> </u><u>metres</u>

Explanation:

Time of flight

t =  \frac{2u \sin( \theta) }{g}

for range, acceleration is zero

from second newton's equation:

S = ut +  \frac{1}{2}  {at}^{2}

but a = 0:

let range be x:

x = ut \\ x =  \frac{2 {u}^{2}  \sin( \theta) }{g}  \\  \\ x =  \frac{ \{2 \times 25 {}^{2}  \sin(30 \degree)  \}}{10}  \\  \\ x = 62.5 \: metres

[ taken g to be 10 m/s² ]

4 0
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Answer:

17 kJ

Explanation:

q = mCΔT

q = (55 kg) (4.184 kJ/kg/K) (360 K − 285 K)

q = 17,000 J

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