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Shtirlitz [24]
3 years ago
12

Although you can see the pencil, it appears broken in the glass of water. This is because

Chemistry
2 answers:
professor190 [17]3 years ago
4 0
I believe that the answer is B. 
Hope this helps
~Perla

Anon25 [30]3 years ago
3 0
The answer is b. but an easier term to remember it by is called "refraction"
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If a drug caused a sudden release of large amounts of calcium in skeletal muscle, from which structure would the calcium come?
lawyer [7]
<span>Sarcoplasmic reticulum</span>
7 0
3 years ago
Read 2 more answers
Determine the correct name for the compound MG3N2
SSSSS [86.1K]
Mg3N2 is Magnesium nitride
5 0
2 years ago
In the compound cah2 calcium has an oxidation number of 2+ and hydrogen has an oxidation number of
sesenic [268]

The oxidation number of H is -1.

Sum of the oxidation numbers in each element = charge of the complex

CaH₂ has 1 Ca atom and 2H atoms. The charge of the complex is zero. Let’s say Oxidation number of H is "a".

Then,

<span>    (+2) + 2 x a = 0 </span>

<span>        +2  + 2a  = 0</span>

                  2a = -2

                    a = -1

Hence, the oxidation number of Hydrogen atom in CaH₂ is -1


7 0
3 years ago
Please help fast! I will give brainliest!
Kaylis [27]

Answer:(c)

Explanation:

3 0
3 years ago
Consider the following intermediate chemical equations.
QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

P_4(s)+6Cl_2\rightarrow 4PCl_3  \Delta H_1=-2439kJ (1)

4PCl_5(g)\rightarrow P_4(s)+10Cl_2(g)  \Delta H_2=3438kJ (2)

Net chemical equation:

PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H=? (3)

Adding 1 and 2 we get,

4PCl_5(g)\rightarrow 4PCl_3(g)+4Cl_2 \Delta H_3=\Delta H_1+\Delta H_2=-2439+3438=1000kJ   (4)

Now dividing equation (4) by 4, we get

PCl_5(g)\rightarrow PCl_3(g)+Cl_2

\Delta H=\frac{\Delta H_3}{4}=\frac{1000kJ}{4}=250kJ   (4)

8 0
3 years ago
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