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2 years ago

The [H3O+] concentration in the rainwater of pH = 4.35 is:

Chemistry

1 answer:

Eva8 [605]2 years ago

5 0

Answer:

5.62 * 10^-5 [H3O+]

Explanation:

10^-4.25 = 5.62 * 10^-5

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I am so bored someone talk

kolezko [41]

Answer:

hello.

Explanation:

you wanted to talk? well here I am

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1 year ago

How many grams of glucose are needed to form 150g of ethanol?

Svetradugi [14.3K]

<span>1 mole glucose gives 2 moles of ethanol

moles of glucose in 2.4 kg = 2400 / 180.18 = 13.320 moles

so moles of ethanol produced = 2* 13.32 = 26.64 moles

weight of ethanol 26.64 * 46.07

=1227.30 gm or 1.23 Kg</span>

6 0

2 years ago

Question 6 of 10

love history [14]

B. Newton’s second law

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2 years ago

A 4.36 g sample of an unknown alkali metal hydroxide is dissolved in 100.0 ml of water. an acid-base indicator is added and the

Fofino [41]

Answer:

(a) $102.6g/mol$

(b) Rubidium

Explanation:

Hello,

This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:

$V_{base}=0.1L; M_{acid}=2.5M, V_{acid}=0.017L\\V_{base}M_{base}=V_{acid}M_{acid}$

Solving for the molarity of base we've got:

$M_{base}=\frac{M_{acid}*V_{acid}}{V_{base}}=\frac{2.50M*0.017L}{0.1L} =0.425M=0.425mol/L$

Now, we can compute the moles of the base as:

$n_{base}=0.425mol/L*0.1L=0.0425mol$

(a) Now, one divides the provided mass over the previously computed moles to get the molecular mass of the unknown base:

$\frac{4.36g}{0.0425mol} =102.6g/mol$

(b) Subtracting the atomic mass of oxygen and hydrogen, the metal's atomic mass turns out into:

$102.6g/mol-16g/mol-1g/mol=85.6g/mol$

So, that atomic mass dovetails to the Rubidium's atomic mass.

Best regards.

8 0

2 years ago

Prandtl number in heat transfer analogues to which dimension less number in mass transfer. a) Schmidt number b) Sherwood number

Cloud [144]

Answer:

a) Schmidt number

Explanation:

Prandtl number in heat transfer is analogues to Schmidt number in mass transfer.

Prandtl number in heat transfer is the ration of momentum diffusivity to the heat diffusivity.

$P_r = \frac{\nu}{\alpha}$

Whereas, Schmidt number in mass transfer is the ratio of momentum diffusivity to the mass diffusivity.

$S_c= \frac{\nu}{\nu_{AB}}$

5 0

2 years ago