2 years ago

Calculate the amount of mole of iron produced from the reaction of 15.9 grams of iron oxide.

Chemistry

1 answer:

Usimov [2.4K]2 years ago

3 0

Answer:

0.19875

Explanation:

nFe2O3=0.099375

nFe=2nFe2O3=0.19875

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g Ammonium nitrate was the oxidizing agent used that damaged the New York World Trade Center in 1993 and the Federal Building in

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Answer: $51.3\times 10^3$ kJ

Explanation:

The thermochemical equation for decomposition of ammonium nitrate is:

$NH_4NO_3(s)\rightarrow N_2O(g)+2H_2O(g)$ $\Delta H=-82.1kJ$

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass= 50.0 kg = $50.0\times 10^3g$ (1kg=1000g)

$\text{Number of moles of ammonium nitrate}=\frac{50.0\times 10^3g}{80g/mol}=0.625\times 10^3moles$

According to stoichiometry:

1 mole of $NH_4NO_3$ gives = 82.1 kJ of heat

Thus $0.625\times 10^3moles$ of $NH_4NO_3$ give = $\frac{82.1}{1}\times 0.625\times 10^3=51.3\times 10^3$ kJ of heat

Thus $51.3\times 10^3$ kJ of heat is evolved from the decomposition of 50.0 kg of ammonium nitrate.

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