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wariber [46]
1 year ago
7

Think about the animals in an arctic ecosystem. How would those animals adapt over time if global temperatures rise over the nex

t several hundred years?
Chemistry
1 answer:
brilliants [131]1 year ago
5 0

Given the fact that we are seeing a rise in the temperature of the globe, the artic animals in that ecosystem must adapt by a reduction in the rate of metabolism.

<h3>What is global warming?</h3>

Several evidences continue to emerge that the temperature of the earth have continued to increase and this is largely due to the fact that since the turn of the twentieth century and the rise of industrialization, there have been a rise in the emission of the carbon dioxide and other green house gases into the environment. As a result of this, the temperature of the earth has continued to rise steadily leading to the melting of the ice cover and the destruction of ecosystems that are found around the artic regions of the earth.

Now, we know that an organism is able to adapt to the changes that occur in its habitat by being able to alter some of its structure and function.

Given that the organisms that live in the artic are adapted to cold regions and low temperatures, the metabolic rate of the organisms is high in order to produce heat.

As a result of the rise in global temperatures, the organisms would have to reduce their rate of metabolism.

Learn more about global warming:brainly.com/question/12908180

#SPJ1

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PLEASE EXPLAIN CORRECTLY! THX=)
tankabanditka [31]
A way to explain it is that back then all the continents were together but soon after drifted apart the were in the same place sort of put they drifted apart so that's sorta what happened. Hope that helps a little
8 0
2 years ago
Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)
Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s)   (1)

We can write the above reaction in <u>two reactions</u>, one for oxidation and the other for reduction:

  • Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻   (2)

  • Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s)    (3)

We can see that Li⁰ is oxidizing to Li⁺ (by <u>losing</u> one electron) in the lithium acetate (<em>reaction 2</em>) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by <u>gaining</u> two <em>electrons</em>) (<em>reaction 3</em>).  

We must remember that the reducing agent is the one that will be oxidized by <u>reducing another element</u> and that the oxidizing agent is the one that will be reduced by <u>oxidizing another species</u>.

In reaction (1), the<em> reducing agent</em> is <em>Li</em> (it is oxidizing to Li⁺), and the <em>oxidizing agent </em>is<em> Fe(CH₃COO)₂</em> (it is reducing to Fe⁰).  

Therefore, the reducing agent in reaction (1) is lithium (Li).  

 

Learn more here:

  • brainly.com/question/10547418?referrer=searchResults
  • brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

3 0
2 years ago
A
MArishka [77]

Answer:

B. bias

Explanation:

7 0
2 years ago
Read 2 more answers
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

7 0
3 years ago
HURRY
Ugo [173]

Answer:

11.647g of water may be produced.

Explanation:

chemistry of the reaction:

2O2 + 2H2 ----> 2H2O + O2

64g + 4g yields 36g of water,

20g + 2g yields 11.647058824g of water

5 0
3 years ago
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