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Keith_Richards [23]
3 years ago
5

Can someone help me fill out the chart and explain what i should do, please?

Chemistry
1 answer:
Alina [70]3 years ago
5 0

To determine the electronegativity for each bond you need to calculate the difference of electronegativity of the atoms forming the bond.  

If the difference is equal or greater than 1.7 you have an ionic bond.

If the difference is between 0.4 and 1.6  you have a polar covalent bond.

If the difference is between 0 and less than 0.4 you have a nonpolar covalent bond.  

1) In NH₃ there is a nitrogen - hydrogen bond.  

electronegativity of nitrogen - electronegativity of hydrogen =

3 - 2.2 = 0.8 → polar covalent bond

2) In N₂ there is a nitrogen-nitrogen bond.

electronegativity of nitrogen - electronegativity of nitrogen =

3 - 3 = 0 → nonpolar covalent bond

3) In H₂O there is an oxygen - hydrogen bond.  

electronegativity of oxygen - electronegativity of hydrogen =

3.5 - 2.2 = 1.3 → polar covalent bond

4) In PCl₃ there is a chlorine - phosphorus bond.  

electronegativity of chlorine - electronegativity of phosphorus = 3 - 2.1 = 0.9 → polar covalent bond

4) In HBr there is a bromine - hydrogen bond.  

electronegativity of bromine - electronegativity of hydrogen = 2.8 - 2.2 = 0.6 → polar covalent bond

5) In MgCl₂ there is a chlorine - magnesium bond.  

electronegativity of chlorine - electronegativity of magnesium = 3 - 1.2 = 1.8 → ionic bond

6) In F₂ there is a fluorine - fluorine  bond.  

electronegativity of fluorine - electronegativity of fluorine =

4 - 4 = 0 → nonpolar covalent bond

7) In CO₂ there is an oxygen - carbon bond.  

electronegativity of oxygen- electronegativity of carbon =

3.5 - 2.5 = 1 → polar covalent bond

8) In LiCl there is a chlorine - lithium bond.  

electronegativity of chlorine - electronegativity of lithium =

3 - 1 = 2 → ionic bond

9) In Na₂O there is an oxygen - sodium bond.

electronegativity of oxygen - electronegativity of sodium =

3.5 - 0.9 = 2.6 → ionic bond

10)  In CCl₄ there is a chlorine - carbon bond.  

electronegativity of chlorine - electronegativity of carbon =

3 - 2.5 = 0.5 → polar covalent bond

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PolarNik [594]

Answer:

8.38 mL

Explanation:

1- The combustion reaction of ethanol (C2H5OH) in the presence of oxygen (O2) has as reaction products carbon dioxide (CO2) and water (H2O), the equation equaled is:

<em>C2H5OH (l) + 3 O2 (g) CO2 2 CO2 (g) + 3 H2O (l) </em>

2- By establishing the stoichiometric relationship between ethanol and water, you can calculate the number of molecules that will be created from the initial amount of alcohol molecules:

6,022x10 23 molecules of C2H5OH (1 mol) ___ 3 x 6,022x10 23 molecules of H2O (3 moles)

9.32x10 22 C2H5OH molecules _____ X = 2.80x10 23 H2O molecules

<em>Calculation: </em>

9.32x10 22 x (3 x 6.022x10 23) / 6.022x10 23 = 2.80x10 23 H2O molecules

3- Once the number of water molecules formed is obtained, with the molar mass the mass can be determined:

6.022x10 23 H2O molecules _____ 18.02 g

2.80x10 23 molecules of H2O _____ X = 8.38 g of H2O

<em>Calculation: </em>

2.80x10 23 x 18.02 g / 6.022x1023 = 8.38 g of H2O

4- Finally, having the density of water, you can calculate the volume that formed:

d = m / V  --> V = m / d

V = 8.38 g / 1.00 mL = 8.38 mL

The answer is that 8.38 mL of water is formed

5 0
3 years ago
write chemical equations of photosynthesis and cellular respiration and show if carbon is oxidized or reduced
irina [24]

Answer:

Explanation:

  • The chemical reaction for cellular respiration  is as follows -

C₆H₁₂O₆ ( Glucose ) + 6 O₂ ( Oxygen ) --------------> 6CO₂  ( Carbon dioxide ) +  6H₂O ( Water ) + 38 ATP molecules ( Energy ) .

This is an example of oxidation of carbon .

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6CO₂  ( Carbon dioxide ) + 6H₂O ( Water ) --------------> C₆H₁₂O₆( Glucose ) + 6 O₂  ( Oxygen ).

This is an example of reduction of carbon .

6 0
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QUESTION 33 Which of the following correctly expresses 7,000,000,000 in scientific notation? 70 x 106 7 x 109 .7 x 10-7
ki77a [65]
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Hatshy [7]

Answer:

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Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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From the balanced equation above,

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Next, we shall determine the number of mole of Zn required to produce 0.5 mole of H₂. This can be obtained as follow:

From the balanced equation above,

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Therefore, 0.5 mole of Zn will also react to produce to 0.5 mole of H₂.

Thus, 0.5 mole of Zn is required.

Finally, we shall determine the mass of 0.5 mole of Zn. This can be obtained as follow:

Mole of Zn = 0.5 mole

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Mass of Zn = 32.7 g

Thus, 32.7 g of Zn is required to produce 0.5 mole of H₂.

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