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Keith_Richards [23]
3 years ago
5

Can someone help me fill out the chart and explain what i should do, please?

Chemistry
1 answer:
Alina [70]3 years ago
5 0

To determine the electronegativity for each bond you need to calculate the difference of electronegativity of the atoms forming the bond.  

If the difference is equal or greater than 1.7 you have an ionic bond.

If the difference is between 0.4 and 1.6  you have a polar covalent bond.

If the difference is between 0 and less than 0.4 you have a nonpolar covalent bond.  

1) In NH₃ there is a nitrogen - hydrogen bond.  

electronegativity of nitrogen - electronegativity of hydrogen =

3 - 2.2 = 0.8 → polar covalent bond

2) In N₂ there is a nitrogen-nitrogen bond.

electronegativity of nitrogen - electronegativity of nitrogen =

3 - 3 = 0 → nonpolar covalent bond

3) In H₂O there is an oxygen - hydrogen bond.  

electronegativity of oxygen - electronegativity of hydrogen =

3.5 - 2.2 = 1.3 → polar covalent bond

4) In PCl₃ there is a chlorine - phosphorus bond.  

electronegativity of chlorine - electronegativity of phosphorus = 3 - 2.1 = 0.9 → polar covalent bond

4) In HBr there is a bromine - hydrogen bond.  

electronegativity of bromine - electronegativity of hydrogen = 2.8 - 2.2 = 0.6 → polar covalent bond

5) In MgCl₂ there is a chlorine - magnesium bond.  

electronegativity of chlorine - electronegativity of magnesium = 3 - 1.2 = 1.8 → ionic bond

6) In F₂ there is a fluorine - fluorine  bond.  

electronegativity of fluorine - electronegativity of fluorine =

4 - 4 = 0 → nonpolar covalent bond

7) In CO₂ there is an oxygen - carbon bond.  

electronegativity of oxygen- electronegativity of carbon =

3.5 - 2.5 = 1 → polar covalent bond

8) In LiCl there is a chlorine - lithium bond.  

electronegativity of chlorine - electronegativity of lithium =

3 - 1 = 2 → ionic bond

9) In Na₂O there is an oxygen - sodium bond.

electronegativity of oxygen - electronegativity of sodium =

3.5 - 0.9 = 2.6 → ionic bond

10)  In CCl₄ there is a chlorine - carbon bond.  

electronegativity of chlorine - electronegativity of carbon =

3 - 2.5 = 0.5 → polar covalent bond

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1. calculate the the reaction of gas, F 2 (g) with H 2 O(l) water form and O 2 (e).
Sever21 [200]

hope this helped.:)

Explanation:

Yes, the number of moles of oxygen gas produced by your reaction under those conditions for pressure and temperature will be 0.0025.

Hydrogen peroxide,  

H

2

O

2

, decomposes to give water and oxygen gas according to the balanced chemical equation

2

H

2

O

2

(

a

q

)

→

2

H

2

O

(

l

)

+

O

2

(

g

)

You've collected 0.061 L of oxygen gas at 295.15 K and 1 atm, so you've got all the data you need to calculate the number of moles of oxygen gas produced by using the ideal gas law equation

P

V

=

n

R

T

⇒

n

=

P

V

R

T

n

O

2

=

1

atm

⋅

0.061

L

0.082

L

⋅

atm

mol

⋅

K

=

0.0025 moles

So, if this was your first question, then yes, your reaction produced 0.0025 moles of oxygen gas.

I find the second part of your question to be a little confusing. You were given the density of the hydrogen peroxide solution, so are you supposed to use that to determine the theoretical number of moles of oxygen for this reaction?

I'm not sure what  

100%

H

2

O

2

=

1.02 g/mL  

means, do you have a certain volume of hydrogen peroxide solution?

SIDE NOTE According to the additional information posted by Heather, it turns out that the initial hydrogen peroxide solution had a volume of 5 mL.

Even with the volume of the initial solution, you'd need its percent concentration to try and determine exactly how many moles you had present before the reaction.

Once you know how many moles of hydrogen peroxide you had, assume that all of the react and use the  

2

:

1

mole ratio that exists between  

H

2

O

2

and  

O

2

to get the number of moles of oxygen your reaction could have produced.

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