All categories

3 years ago

Identify how the colligative properties of a solvent change when a solute is added, forming a solution.

1 answer:

8 0

Colligative properties are properties that depends on ratio of the number of solute to the number of solvent . Colligative properties are essentially solvent properties that are changed by the presence of solute . The solute particles displaces some solvent molecules in the liquid phase and therefore reduce the concentration of solvent. So basically colligative properties are independent of the nature of the solute.

You might be interested in

What are the names and symbols for the three different radioactive particles? What are each made of

Liono4ka [1.6K]

Its alpha, gamma, and beta

3 0

3 years ago

TTILA U.

horrorfan [7]

Answer:

Explanation:

If it is said that an electric bulb contains 60 watts, that implies that the electric bulb will have to consume a required amount of energy of about 60 joules in a second.

Mathematically:

Power rating = Energy consumed ÷ time

The electronic configuration typically implies the arrangement of electrons in atomic orbitals. The electronic configuration of Calcium (Ca) in it subshell method is:

$\mathbf{Ca (20) = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 }$

4 0

3 years ago

All of the following statements about different elements are true EXCEPT:a) barium is an alkali earth metalb) manganese is a tra

stich3 [128]

Answer:

The statement that is not true is: c) Sulfur is considered a metalloid

Explanation:

To answer this kind of questions your best tool is a periodic table.

The periodic table shows the elements ordered by increasing atomic number (number of protons), in an arragement of rows and columns. In such arrangement, the elements appear classified as metals, non-metals, and metaloids.

Roughly metals are on the left side of the table, nonmetals are on the right side, and metalloids are a reduced group that are in a kind of step ladder dividing the metals and nonmetals.

With that, you can follow this procedure for each of the answer choices:

a) Barium is an alkali earth metal:

TRUE. Barium, Ba, has atomic number 56, is in the column (group) number 2, which is the group of the alkali earth metals.

b) Manganese is a transition metal:

TRUE. Manganese, Mn, has atomic number 25 and is in the column 7. The columns 3 through 12 enclose the transition metals. So, manganese is a transition metal.

c) Sulfur is considered a metalloid.

FALSE. Sulfur, S, has atomic number 16, is in the column 16, (right below oxygen) and is classified as a nonmetal.

d) Krypton is one of the noble gasses

TRUE. Krypton, Kr, has atomic number 36, and is in the column 18. This column includes all the noble gases, which are elements whose valence shells are complete (2 electrons in the case of He and 8 electrons in all the other cases).

This group is named noble gases because the elements have very low reactivity, so they are almos inert.

e) Iodine is a halogen

TRUE. Iodine, I, is the element with atomic number 53, and is in the column 17. This column includes all the halogens (F, Cl, Br, I, At, and the most recently discovered Ts).

6 0

4 years ago

an asrnout in space might fell weighless but there still gravitaional attraction between the astournout and earth . Which to fac

dezoksy [38]

Answer:

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

5 0

3 years ago

The pressure and temperature of N² and gas drops from 303kPa at 300K to 202²kPa at -73°C. If the initial volume is 2L, find the

alex41 [277]

Answer:

Gjvb

Explanation:

Using the combined gas law equation as follows:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to this question;

T1 = 300K

T2 = -73 + 273 = 200K

P1 = 303kPa

P2 = 202kPa

V1 = 2L

V2 = ?

Using the above formula:

303 × 2/300 = 202 × V2/200

606/300 = 202V2/200

Cross multiply;

606 × 200 = 300 × 202V2

121200 = 60600V2

V2 = 121200/60600

V2 = 2L

The new volume is 2L

8 0

3 years ago