Answer: most store-bought isnt
Explanation:
there typically a lot of addivitves
The question is incomplete, here is the complete question:
What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)
<u>Answer:</u> The volume of HCl neutralized is 1.25 mL
<u>Explanation:</u>
To calculate the volume of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of stomach acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the volume of HCl neutralized is 1.25 mL
Answer:
I’m not sure probably false
Explanation:
Answer:
The mass of CO22 in total is 264 g.
The atomic mass for C is 12 g / mole.
The molar mass for CO22 is (12 + (2 × 16)) = 44 g / mole.
m C = (12 / 44) × 264 = 72 g
So, there are 72 g of C in 264 g of CO2
Explanation:
there's the answer have a good day.
Answer:
C: It is conserved
Explanation:
The reaction neither lost (exothermic) or gained (endothermic) energy, therefore the total energy remained the same and was conserved.