KCIO3 → KCI + O2
First you have to count all the atoms of each element in both sides of the reaction, in this case:
Left side: there is one K atom, one Cl atom and 3 O atoms
Right side: there is one K atom, one Cl atom and 2 O atoms
K and Cl are balanced but O isn't
To balance O you can add a coefficient to O2 in the right side of the equation like this:
KCIO3 → KCI +3 O2
Now you have 6 oxygen atoms in the right side but only 3 in the left side, so you can add a coefficient to KClO3:
2KCIO3 → KCI +3 O2
And finally, Balance K and Cl again by adding a 2 as a coefficient for KCl
2KCIO3 → 2KCI +3 O2
Now both sides have the same amount of atoms of each element (2 K atoms, 2 Cl atoms and 6 O atoms)
The Higgs Boson is the only known particle that gives mass to other particles/atoms. Particle physicists and theoretical physicists are arguing that there are more than one type of Higgs Boson.
Answer:
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Please make sure to re-write this on your own so your teacher doesn't think that your cheating!</em></h3>
Explanation:
A neutral atom will have the same number of electrons does protons. Since it has 4 protons, it must have an atomic number of 4. (That will make it beryllium.) Since it has 4 protons and 5 neutrons, it has a mass number of 9.
So the answer is 9
Answer:
You must remove 
.
Explanation:
There are three heat transfers in this process:
Total heat = cool the vapour + condense the vapour + cool the liquid
q = q₁ + q₂ + q₃
q = nC₁ΔT₁ + nΔHcond + nC₂ΔT₂
Let's calculate these heat transfers separately.
Data:
You don't give "the data below", so I will use my best estimates from the NIST Chemistry WebBook. You can later substitute your own values.
C₁ = specific heat capacity of vapour = 90 J·K⁻¹mol⁻¹
C₂ = specific heat capacity of liquid = 115 J·K⁻¹mol⁻¹
ΔHcond = -38.56 kJ·mol⁻¹
Tmax = 300 °C
b.p. = 78.4 °C
Tmin = 25.0 °C
n = 0.782 mol
Calculations:
ΔT₁ = 78.4 - 300 = -221.6 K
q₁ = 0.782 × 90 × (-221.6) = -15 600 J = -15.60 kJ
q₂ = 0.782 × (-38.56) = -30.15 kJ
ΔT = 25.0 - 78.4 = -53.4 K
q₃ = 0.782 × 115 × (-53.4) = -4802 J = 4.802 kJ
q = -15.60 - 53.4 - 4.802 = -50.6 kJ
You must remove of heat to convert the vapour to a gas.
