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2 years ago

What is the total pressure of a container in kpa if the partial pressures are 1.25 atm and 66.7 psi?

Chemistry

1 answer:

STatiana [176]2 years ago

4 0

Answer:

586 kpa(kilopascal/1000 pascals)

Explanation:

given 1.24 atm(standard atmosphere), and 66.7 psi(pound force per square inch).

To find the total pressure we should use dalton's law of partial pressures which is the sum of the pressures of each individual gas.

then we convert them to pascals and divide by 1000 to get the measurement in kilopascal.

knowing that 1 atmosphere is proportional to around 14.696 psi. We can multiply our given measure of atm by that and sum it by psi like so. 1.24×14.6959 = 18.22298.

Then,

18.22298+ 66.7 = 84.92298

psi.

Since 1 psi is proportional to around 6894.76 pascals. 1 psi will be 68.9476 kilopascal. 84.92298 * 6.89476 = 585.523336 ≈ 586

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A sample of PCl5(g) was placed in an otherwise empty flask at an initial pressure of 0.500 atm and a temperature above 500 K. Ov

tia_tia [17]

Answer:

Kp = 0.81666

Explanation:

Pressure of PCl₅ = 0.500 atm

Considering the ICE table for the equilibrium as:

PCl₅ (g) ⇔ PCl₃ (g) + Cl₂ (g)

t = o 0.500

t = eq -x x x

--------------------------------------------- --------------------------

Moles at eq: 0.500-x x x

Given the pressure of PCl₅ at equilibrium = 0.150 atm

Thus, 0.500 - x = 0.150

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The expression for the equilibrium constant is:

$K_p=\frac {P_{PCl_3}P_{[Cl_2}}{P_{PCl_5}}$

So,

$K_p=\frac{x^2}{0.500-x}$

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