Answer:
Formula: Na2S2O3
we get solubility.
Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .
Solution given:
mass of sodium thiosulphate [m1]=25.5g
mass of water [m2]=40g
at temperature [t]=25°C
we have
<u>solubility in g/dm^3</u> :
- =

- =63.75g /litre=63.75g/dm³
<u>solubility in g/dm^3 :63.75g/dm³</u>
<u>n</u><u>o</u><u>w</u>
solubility of the solute in mol/dm^3=:63.75g/dm³/178=0.4 mol/dm³
I’m pretty sure it would be D.
Answer: 1mole
Explanation:
Mole = concentration× Volume (dm3)
Mole = 2× 500/1000
<span>When naming compounds, the first thing you need to do is decide if the compound is ionic or molecular. *Ionic compounds
will contain both metals and non-metals, or at least one polyatomic
ion. *Acids will always include the (aq) symbol beside the formula, and
the name will include the word acid.</span>