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Katarina [22]
3 years ago
6

23592U + 10n → ____10n + 13956Ba + 9436Kr

Chemistry
1 answer:
lapo4ka [179]3 years ago
8 0

Answer:

nice question dont know the answer tho

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A block of aluminum occupies a volume of 15.0 mL and weighs 45 grams.
vladimir2022 [97]
Answer: density equals 3 g/mL

Step by step explanation:

D=m/v
D=45/15
D=3
5 0
3 years ago
When the potential difference across a lamp is 3.3V the current is 0.15 calculate the resistance of the lamp and give the unit
marissa [1.9K]

Answer:

22Ω

Explanation:

Given parameters:

Potential difference  = 3.3V

Current  = 0.15A

Unknown:

Resistance  = ?

Solution:

According to ohm's law, potential difference, current and resistance are related by the expression below;

             V = I R

where V is the voltage

           I is the current

          R is the resistance

          3.3 = 0.15 x R

             R = \frac{3.3}{0.15}   = 22Ω

6 0
2 years ago
How do I answer It ??
IgorC [24]

Recibí tus puntos, lo siento mucho por esto, pero, adiós perra

5 0
3 years ago
Which of the following statements does not describe what he structure of an atom an atom has a small dense center called nucleus
nikklg [1K]

Answer:

inside the nucleus of an atom are protons and electrons.

5 0
2 years ago
Use the molar heat capacity for aluminum from table 1 to calculate the amount of energy needed to raise the temperature of 260.5
Nimfa-mama [501]
Unfortunately, you failed to include the table 1 from which the molar heat capacity of aluminum could have been obtained. However, as a general rule, the heat needed to raise the temperature of a certain substance by certain degrees is calculated through the equation,
                            H = mcpdT
where H is heat, m is mass, cp is specific heat capacity, and dT is change in temperature. From a reliable source, cp for aluminum is equal to 0.215 cal/g°C. Substituting this to the equation,
                               H = (260.5 g)(0.215 cal/g°C)(125°C - 0)
                                        H = 7000.94 cal
6 0
2 years ago
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