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brilliants [131]
3 years ago
5

Ammonia (nh3) involves an unequal sharing of electrons between nitrogen and three hydrogen atoms. what type of bonding does ammo

nia have?
Chemistry
1 answer:
Crank3 years ago
7 0
The molecules in ammonia are bonded together by covalent bond; this  is the type of bond in which electrons are shared among atoms in the compound. Ammonia is a polar molecule and is made up of one nitrogen atom and three hydrogen atoms. The hydrogen atom in ammonia is bonded to the three hydrogen atoms via sharing of three electron pairs, one with each atom of hydrogen. For each of the three covalent bond formed, one electron is supplied by nitrogen and one by hydrogen atom. 
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Answer:True

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The diagram shows the three steps of the fusion process in the Sun.
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D. Z, X, Y

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Collision of third proton takes place with deuterium and this collision results in formation of Helium-3 along with gamma rays. These gamma rays are also released as sunlight.

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Which process causes the greatest depletion of oxygen from the atmosphere?
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How much energy is required to heat a 40 g sample of ice with an initial temperature of -10°C until it reaches a final temperatu
Elden [556K]

Answer:

The total energy required is 121.56 kJ

Explanation:

The energy required to heat a m = 40g sample of ice is calculated using the following information:

The specific heat of ice =s_{ice} = 2.108 J/g-K

The specific heat of water =s_{water} = 4.187 J/g-K

The specific heat of steam = s_{steam} = 1.996 J/g-K

The latent heat of fusion for ice = L = 336 kJ/kg

The latent heat of vaporisation = l = 2260 kJ/kg

The latent heat of fusion is the amount of energy required to change one kg of ice into water without a change in temperature.

Firstly, we find the energy required to change the temperature of 40 g of ice from -10°C to 0°C.

Energy\:required=ms_{ice}\Delta T\\ \Delta T\:is\:the\:change\:in\:temperature\\Energy\:required=40\times2.108\times(0-(-10))=40\times2.108\times10=843.2J

Then, the energy required to convert 40g of ice at 0°C to water at 0°C.

Energy\:required=mL=40\times336=13440J

Then, the energy required to convert water at 0°C to water at 100°C.

Energy\:required=ms_{water}\Delta T=40\times4.187\times(100-0)=40\times4.187\times100=16748J

The energy required to convert water at 100°C to steam at 100°C.

Energy\:required=ml=40\times2260=90400J\\

The energy required to convert steam at 100°C to steam at 105°C.

Energy\:required=ms_{steam}\Delta T=40\times1.996\times(105-100)=399.2J

Total Energy required = 843.2 + 13440 + 16748 + 90400 + 399.2 = 121560.4J = 121.56 kJ

7 0
3 years ago
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