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JulijaS [17]
2 years ago
8

_______________ is a function of meiosis rather than a function of mitosis. A) Growth B) Repair of wounds Eliminate C) Gamete pr

oduction D) Multiplication of somatic cells
Chemistry
2 answers:
ivanzaharov [21]2 years ago
8 0
The answer is c) gamete production
stepan [7]2 years ago
6 0

The answer would be letter C. Gamete production.

If you'd like to know why:

The sole purpose of meiosis is the production of gametes, or in other words, sex cells. Unlike in mitosis, the daughter cells are not identical to the parent cell. They have half of the number of chromosomes of the parent cell, so in short the cell that is produced is different.

Mitosis on the other hand, produces identical cells, or daughter cells that are identical to the parent cell, which makes them purposeful in growth and wound repair. They produce the same kind of cell, each time.

You might be interested in
Draw the resonance structures for (SCN)".
Phantasy [73]

Answer : The resonance structure of SCN is shown below.

Explanation :

Resonance structure : It is defined as when more than one Lewis structure can be drawn, the molecule or ion is said to have resonance.

Resonance is the concept where electrons (bonds) are delocalized over three or more atoms which cannot be depicted with one simple Lewis structure.

First we have to draw Lewis-dot structure.

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, SCN

As we know that sulfur has '6' valence electrons, carbon has '6' valence electrons and nitrogen has '5' valence electron.

Therefore, the total number of valence electrons in SCN = 6 + 4 + 5 = 15

According to Lewis-dot structure, there are 7 number of bonding electrons and 8 number of non-bonding electrons.

In SCN, carbon atom is the central atom and sulfur and nitrogen are the neighboring atoms.

The resonance structure of SCN is shown below.

3 0
3 years ago
6. Explain the impact on fresh water of:
Paraphin [41]

Fresh water pollutants  are substances which pollute fresh water and  industrial waste, is most harmful fresh water pollutant to man and aquatic organisms.

<h3>What are pollutants?</h3>

Pollutants are substances which cause harm when they are present in the environment.

Pollutants include chemicals such as petroleum and material such as sewage.

The presence of pollutants in freshwater results in water pollution and make the water unfit for drinking purposes and also harms aquatic life in freshwaters.

Some freshwater pollutants include:

  • Farming wastes
  • Household pollutants
  • Industrial wastes
  • Erosion
  • Oil and Gasoline
  • heat

Of these pollutants, the most dangerous fresh water pollutant is industrial wastes as they kill aquatic organisms most due to the presence of harmful chemicals in them.

Therefore, fresh water pollutants such as industrial waste is most harmful to man and aquatic organisms.

Learn more about pollutants at: brainly.com/question/1235358

#SPJ1

5 0
1 year ago
How many molecules are in 13 moles of oxygen?
natima [27]

Answer:

mass/13of molecules .........

8 0
2 years ago
Read 2 more answers
Adding energy to solid water will turn it into ?
love history [14]

Answer:

Energy added to solid water will turn it into liquid water; add energy into liquid water and it will be turned into water vapor.

Explanation:

Adding energy is basically adding heat; the more heat, the more excited the molecules of H2O gets. In solid water, the molecules aren't really moving because they don't have a lot of energy, so it is solid. In liquid water (which is water in room temperature), it has a medium amount of energy; the molecules aren't stuck together but it isn't completely dispersed, so it is in liquid form. However, in water vapor, the energy becomes very high and the molecules are excited. The hydrogen bonds holding the molecules together break and the water is released as a vapor.

5 0
1 year ago
Calculate the molality of a 20.0% by mass ammonium sulfate (nh4)2so4 solution. the density of the solution is 1.117 g/ml.
olasank [31]
Hello!

We have the following data:

m1 (solute mass) = 20 % m/m
M1 (Molar mass of solute) (NH4)2 SO4 = ?
m2 (mass of the solvent) = ? (in Kg)

First we find the solute mass (m1), knowing that:

20% m/m = 20g/100mL

20 ------ 100 mL (0,1 L)
y g --------------- 1 L

y = 20/0,1 
y = 200 g --> m1 = 200 g

Let's find Solute's Molar Mass, let's see:

M1 of (Nh4)2SO4
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol

We must find the volume of the solvent and therefore its mass (m2), let us see:

d = 1,117 g/mL
m = 200 g
v (volumen of solute) = ?

d =  \dfrac{m}{V} \to V =  \dfrac{m}{d}

V =  \dfrac{200\:\diagup\!\!\!\!g}{1,117\:\diagup\!\!\!\!g/mL} \to V = 179\:mL\:(volumen\:of\:solute)

<span>The solvent volume will be:
</span>
1000 -179 => V = 821 mL (volumen of disolvent)

If: 1 mL = 1g

<span>Then the mass of the solvent is:
</span>
m2 (mass of the solvent) = 821 g → m2 (mass of the solvent) = 0,821 Kg

Now, we apply all the data found to the formula of Molality, let us see:

\omega =  \dfrac{m_1}{M_1*m_2}

\omega =  \dfrac{200}{132*0,821}

\omega =  \dfrac{200}{108,372}

\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark

_________________________________
_________________________________


<span>Another way to find the answer:
</span>
We have the following data: 

W (molality) = ? (in molal)
n (number of mols) = ?
m1 (solute mass) = 20 % m/m = 20g/100mL → (in g to 1L) = 200 g
m2 (disolvent mass) the remaining percentage, in the case: 80 % m/m = 800 g → m2 (disolvent mass) = 0,8 Kg
M1 (Molar mass of solute) (NH4)2 SO4 
N = 2*14 = 28
H = (2*4)*1 = 8
S = 1*32 = 32
O = 4*16 = 64
----------------------
M1 of (Nh4)2SO4 = 28+8+32+64 => M1 = 132 g/mol 


<span>Let's find the number of mols (n), let's see:

</span>n =  \dfrac{m_1}{M_1}

n = \dfrac{200}{132}

n \approx 1,5\:mol

Now, we apply all the data found to the formula of Molality, let us see:

\omega =  \dfrac{n}{m_2}

\omega =  \dfrac{1,5}{0,8}

&#10;\boxed{\boxed{\omega \approx 1,8\:Molal}}\end{array}}\qquad\checkmark

I hope this helps. =)
7 0
3 years ago
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