Answer: 14mL
Explanation:
From the question, we've been told that the that the density of Hg(l) at 0°C is about 14 g mL-1.
14g = 1mL
We should note that atomic weight of mercury = 200.59.
Therefore, 1 mol Hg = 200.59 g
Therefore, the answer that is closest to the volume of one mole of Hg(l) at this temperature will be:
= 200.59/14
= 14.3 mL
= 14mL approximately
<span>Sucrose </span>is an example of a polymer separate but equal means that both races get the same thing they just dont get it at the same time.<span />
A. 2-Fluoro-3-Chlorohexane
B. 1-Bromo-2-Chloro-3-Fluorocyclopentane
C. 4-ethyl-5-methylhexane
D. 2,4,5-trimethylheptane
Answer:
81.26% is the percent yield
Explanation:
Based on the reaction:
CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃
<em>Where 1 mole of CaCl₂ in excess of sodium carbonate produces 1 mole of calcium carbonate.</em>
<em />
To solve this question we must find the moles of CaCl2 added = Moles CaCO₃ produced (Theoretical yield). The percent yield is:
Actual yield (0.366g) / Theoretical yield * 100
<em>Moles CaCl₂ = Moles CaCO₃:</em>
0.0500L * (0.0900moles / L) = 0.00450 moles of CaCO₃
<em>Theoretical mass -Molar mass CaCO₃ = 100.09g/mol-:</em>
0.00450 moles of CaCO₃ * (100.09g / mol) = 0.450g of CaCO₃
Percent yield = 0.366g / 0.450g * 100
81.26% is the percent yield
Answer:
Cytoplasm.
Explanation:
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