Answer:
The temperature to the nearest 0.5°C is 98.5°C
Answer:
Considering the half-life of 10,000 years, after 20,000 years we will have a fourth of the remaining amount.
Explanation:
The half-time is the time a radioisotope takes to decay and lose half of its mass. Therefore, we can make the following scheme to know the amount remaining after a period of time:
Time_________________ Amount
t=0_____________________x
t=10,000 years____________x/2
t=20,000 years___________x/4
During the first 10,000 years the radioisotope lost half of its mass. After 10,000 years more (which means 2 half-lives), the remaining amount also lost half of its mass. Therefore, after 20,000 years, the we will have a fourth of the initial amount.
No - a precipitation will occur though. Potassium nitrate is soluble in water, so the potassium and nitrate ions will remain spectator ions and stay in solution. Lead (II) hydroxide is not soluble, and will precipitate out of solution to form a solid product.
The chemical contractor has to retrieve the chemical and a identification analysis would have to be conducted
Answer:
The Equilibrium will shift towards the left.
Explanation:
The reaction for the formation of nitric oxide is follows,
Expression for reaction quotient is as follows,
![Q=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
Putting the values according to the data given and calculating reaction quotient for the reaction
So, the reaction quotient is 0.16.
and the value of K is 0.01 .
Q>K
Since the value of K is less than Q, therefore the reaction will shift towards left.
