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Mars2501 [29]
3 years ago
10

The capacity of a muscle to continue contracting over a period of time without fatigue is called:

Chemistry
1 answer:
siniylev [52]3 years ago
6 0
<span>B. muscular endurance

</span>The capacity of a muscle to continue contracting over a period of time without fatigue is called muscular endurance.
NOT:
A. muscular strength. 
<span>C. cardiovascular endurance. </span>
<span>D. power.</span>
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describe characteristics of different climate zones as they relate to latitude,elevation,and proximity to bodies of water. (scie
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They or on the southern hysteric watch it on youtube (latitude and longitude song 1 direction remix by the history teachers)
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A compound made of two elements, iridium (Ir) and oxygen (O), was produced in a lab by heating iridium while exposed to air. The
natima [27]
1) Compund Ir (x) O(y)

2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g

3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g

4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g

5) Convert grams to moles

moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles

moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131

6) Find the proportion of moles

Divide by the least of the number of moles, i.e. 0.00656

Ir: 0.00656 / 0.00656 = 1

O: 0.0131 / 0.00656 = 2

=> Empirical formula = Ir O2 (where 2 is the superscript for O)

Answer: Ir O2
5 0
3 years ago
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Which best defines color?
katrin [286]

Answer:

its A

Explanation:

The definition of color is a component of light which is separated when it is reflected off of an object. The appearance of objects or light sources described in terms of the individual's perception of them, involving hue, lightness, and saturation for objects, and hue, brightness, and saturation for light sources.

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2 years ago
Question 1 of 30
Ksivusya [100]
The answer will be A
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3 years ago
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A calorimeter contains 100 g of water at 39.8 ºC. A 8.23 g object at 50 ºC is placed inside the calorimeter. When equilibrium ha
Tju [1.3M]
When equilibrium has been reached so, according to this formula we can get the specific heat of the unknown metal and from it, we can define the metal as each metal has its specific heat:

Mw*Cw*ΔTw = Mm*Cm*ΔTm

when 
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Cw → specific heat of water
ΔTw → difference in temperature for water 

Mm→ mass of metal
Cw→ specific heat of the metal
ΔTm → difference in temperature for metal

by substitution:

100g * 4.18 * (40-39.8) = 8.23 g * Cm * (50-40)

∴ Cm = 83.6 / 82.3 = 1.02 J/g.°C

when the Cm of the Magnesium ∴ the unknown metal is Mg
6 0
3 years ago
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