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They are different by a phase shift of pi/2
Answer:
Explanation:
Relation between ΔG₀ and K ( equilibrium constant ) is as follows .
lnK = - ΔG₀ / RT

The value of R and T are same for all reactions .
So higher the value of negative ΔG₀ , higher will be the value of K .
Mg(s) + N₂0(g) → MgO(s) + N₂(g)
has the ΔG₀ value of -673 kJ which is highest negative value . So this reaction will have highest value of equilibrium constant K .
The molecular structure of 1-nitrobutane is
. The structure of 1-nitrobutane is shown below.
An atom's formal charge would be determined by the covalent model of chemical bonding, which assumes that almost all chemical bonds include equal sharing of electrons among all atoms, regardless their relative electronegativity.
The structure for 1-nitrobutane, making sure to add all non-zero formal charges
There are four kind of molecule present in 1-nitrobutane and they are carbon, hydrogen , nitrogen and oxygen. Nitrogen is bonded with two oxygen atom out of them one oxygen atom is attached with single bond and second oxygen atom is bonded with double bond. Nitrogen has positive charge whereas oxygen has negative charge.
It is a kind of alkane in with nitro group is attached with alkane group.
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Answer:
—COOH
Explanation:
—COOH, acid group, containing 3 elements, C, carbon, O, oxygen, and H, hydrogen.