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3 years ago

5

A scientist reports a measurement of the temperature of the surface of a newly discovered planet as negative 20 Kelvin. What con

clusion can you draw from this report

1 answer:

jarptica [38.1K]3 years ago

3 0

Answer:

The temperature of this newly discovered planet violates the third law of thermodynamic, there is a mistake in this value.

Explanation:

The third law of the Thermodynamic says:

<u> At zero kelvin all molecular movement stops, which means that the entropy will be zero at this temperature.</u>

So we can say there is no thermodynamic system that has temperature values less than 0 K.

The conclusion of the report will be.

The temperature of this new planet violates the third law of thermodynamic, there is a mistake in this value.

I hope it helps you!

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Which two forms of energy travel in waves

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If the length and linear density are constant, the frequency is directly proportional to the square root of the tension.

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3 years ago

You are comparing a reaction that produces a chemical change and one that produces a physical change. What evidence could you us

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Answer: A chemical change results from a chemical reaction, while a physical change is when matter changes forms but not chemical identity. Examples of chemical changes are burning, cooking, rusting, and rotting. Examples of physical changes are boiling, melting, freezing, and shredding. Often, physical changes can be undone, if energy is input.

Explanation: hope this helps have a good day

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4 years ago

To initiate a nuclear reaction, an experimental nuclear physicist wants to shoot a proton into a 5.50-fm-diameter 12C nucleus. T

Crazy boy [7]

Answer:

The value is $u = 3.23 *10^{7} \ m/s$

Explanation:

From the question we are told that

The diameter of the nucleus is $d = 5.50 \ fm = 5.50 *10^{-15} \ c$

The charge of the proton that makes up the nucleus is $Q_2 = \frac{12}{2} * 1.60 *10^{-19} =9.6*10^{-19} \ C$

The energy to be impacted is $KE_f = 2.30 \ MeV = 2.30 *10^{6} \ eV = 2.30 *10^{6} * 1.60 *10^{-19} = 3.68*10^{-13} \ J$

Generally the radius of the nucleus is mathematically represented as

$r = \frac{d}{2}$

=> $r = \frac{5.50 *10^{-15}}{2}$

=> $r = 2.75 *10^{-15} \ m$

Generally from the law energy conservation we have that

$Initial \ total \ energy \ of the \ proton = final \ total \ energy \ of the \ proton$

i.e

$T_i = T_f$

Here

$T_i = KE_i + PE_i$

Here $KE_i$ is the initial kinetic energy which is mathematically represented as

$KE_I = \frac{1}{2} * m * u ^2$

Here $PE_i$ is the initial potential energy of the proton and the value is 0 J given that the proton is moving

Also $T_f$ is mathematically represented as

$T_f = KE_f + PE_f$

Here

$PE_f$ is the final potential energy which is mathematically represented as

$PE_f = \frac{k * Q_1 * Q_2}{r}$

Here $Q_1$ is the charge on the proton with a value of $Q_1 = 1.60 *10^{-19} \ C$

So

$PE_f = \frac{9*10^{9} *(1.60 *10^{-19} ) * ( 9.6 *10^{-19})}{ 2.75 *10^{-15}}$

=> $PE_f = 5.027 *10^{-13 } \ J$

So

$KE_i + PE_i = KE_f + PE_f$

=> $\frac{1}{2} * m * u ^2 +0 = 3.68*10^{-13} + 5.027 *10^{-13 }$

Here m is the mass of the moving proton with value $m = 1.67*10^{-27} \ kg$

So

$\frac{1}{2} * 1.67*10^{-27} * u ^2 +0 = 3.68*10^{-13} + 5.027 *10^{-13 }$

=> $u = \sqrt{\frac{3.68*10^{-13} + 5.027 *10^{-13 }}{0.5 * 1.67*10^{-27}} }$

=> $u = 3.23 *10^{7} \ m/s$

5 0

3 years ago

Condensation happens when moist air ____. A. gains heat by radiation and warms B. warms adiabatically as it sinks to a lower ele

alina1380 [7]

Answer:

C. cools adiabatically as it sinks to a lower elevation

Explanation:

Condensation is the phenomenon where there is a change of the state of matter from gas phase to liquid phase. Vaporization is the reverse of condensation. If a process occurs without the transfer of heat and mass of a thermodynamic system with its surroundings then it is known as an adiabatic process.

Moist air consists of water in gaseous state, so when it is cooled without any exchange of mass or heat there is change of phase.

5 0

3 years ago