Answer:
Part A
The volume of the gaseous product is
Part B
The volume of the the engine’s gaseous exhaust is
Explanation:
Part A
From the question we are told that
The temperature is
The pressure is
The of
The chemical equation for this combustion is
The number of moles of that reacted is mathematically represented as
The molar mass of is constant value which is
So
The gaseous product in the reaction is and water vapour
Now from the reaction
2 moles of will react with 25 moles of to give (16 + 18) moles of and
So
1 mole of will react with 12.5 moles of to give 17 moles of and
This implies that
0.8754 moles of will react with (12.5 * 0.8754 ) moles of to give (17 * 0.8754) of and
So the no of moles of gaseous product is
From the ideal gas law
making V the subject
Where R is the gas constant with a value
Substituting values
Part B
From the reaction the number of moles of oxygen that reacted is
The volume is
No this volume is the 21% oxygen that reacted the 79% of air that did not react are the engine gaseous exhaust and this can be mathematically evaluated as
Substituting values
The answer is (B) non metals are not very good at coducting electricity.
Hope this helps :).
Answer:
About 19.64 pounds of carbon dioxide are produced from burning a gallon of gasoline. On the other hand, 22.38 pounds of carbon dioxide are produced from burning a gallon of diesel. So, different fossil fuels will give different amounts of carbon dioxide to be released.
Explanation:
Answer: In an open system the vapor pressure is equal to the outside air pressure.
Explanation:
An open system is a system that is capable of exchanging both matter and energy with its surroundings.
For example, a hot cup of coffee is an open system as the cup is not covered with a lid. Therefore, heat energy from the coffee goes into the surroundings.
Vapor pressure is defined as the ability of a substance to change into vapor state. pressure
Therefore, we can conclude that in an open system the vapor pressure is equal to the outside air pressure.
For the chemical reactiom to be at equilibrium:
1- The rate of forward reaction must be equal to the rate of the reverse reaction.
2- The mass of EACH element must be equal before and after the reaction (no NET change in mass), otherwise the equilibrium will shift.
Important note: you need to check the mass of each element before and after the reaction (i.e, reactants side and products side) and the not the mass of the system as a whole. This is because the mass of the whole system will be preserved whether the system is at equilibrium or not (this is the fundamental law of mass conservation)