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FromTheMoon [43]
3 years ago
8

How many elements are in the second group? (column)

Chemistry
1 answer:
zavuch27 [327]3 years ago
6 0
Of the periodic table?
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8. 53.4 mL of a 1.50 M solution of NaCl is on hand, but you need some 0.800 M
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8. 100.13 ml
9. 75 ml
10. 1066.7 ml, hope that's help
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3 years ago
Which contains elements with similar properties in the periodic table? A.) a period B.) a column C.) a row
zysi [14]

b............................................

3 0
3 years ago
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What is the volume of a balloon if it contains 3.2 moles of helium at a temperature of 20. °C and standard pressure?
KatRina [158]

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1.14 mol

Explanation:

3 0
3 years ago
Compare the solubility of silver chromate in each of the following aqueous solutions: Clear All 0.10 M AgCH3COO 0.10 M Na2CrO4 0
slavikrds [6]

Solution :

Comparing the solubility of silver chromate for the solutions :

$0.10 \ M \ AgCH_3COO$    -----     Less soluble than in pure water.

$0.10 \ M \ Na_2CrO_4$   ----- Less soluble than in pure water.

$0.10 \ M \ NH_4NO_3$   -----   Similar solubility as in the pure water

$0.10 \ M \ KCH_3COO$   -----   Similar solubility as in the pure water

The silver chromate dissociates to form :

$AgCrO_4 (s) \rightleftharpoons 2Ag^+ (aq) +CrO_4^{2-}(aq)$

When 0.1 M of $AgCH_3COO^-$ is added, the equilibrium shifts towards the reverse direction due to the common ion effect of Ag^+, so the solubility of Ag_2CrO_4 decreases.

Both AgCH_3COO and $KCH_3COO$ are neutral mediums, so they do not affect the solubility.

 

4 0
3 years ago
I AM GIVING BRAINLIEST PLEASEE HELPPPP I NEED HELPPPPPP PLEAEEEEEE
True [87]

Answer:

0.479 M or mol/L

Explanation:

So Molarity is moles/litres of solution...often written as M=mol/L

So here we are given grams of BaCl2 which we have to convert to moles. To convert to moles of BaCl2 we have to divide 63.2 g BaCl2 by molar mass of BaCl2 which is 208.23 g/mol so you get 63.2/208.23 = 0.3035 moles of BaCl2

Second step is converting the 634mL to litres by simply dividing by 1000 because we know 1 litre has 1000ml so 634/1000 = 0.634L

Now we just plug these guys in our molarity formula M=mol/L

M= 0.3035/0.634 = 0.479 M or mol/L

3 0
3 years ago
Read 2 more answers
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