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FromTheMoon [43]
4 years ago
8

How many elements are in the second group? (column)

Chemistry
1 answer:
zavuch27 [327]4 years ago
6 0
Of the periodic table?
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What is the missing number in the nuclear reaction shown below 175 78 pt?
Dmitry [639]
Above question is incomplete. Complete question is
<span>What is the missing number in the nuclear reaction 175 78 pt -- 4 2 He plus 76 Os?
....................................................................................................................
Solution:

Reaction involved in present nuclear event is 
</span>175 78 Pt      →          4 2 He          +          76 Os

In above nuclear reaction, atomic mass number of Os is missing. The atomic mass number of Os = 175 - 4 = 171

Thus, complete nuclear can be written as
175 78 Pt      →          4 2 He          +       171  76 Os

3 0
3 years ago
Read 2 more answers
What is the mass in grams of<br>1.0mole of (NH4)2S?​
jeka94
7272727282828383jsjsjsj
7 0
3 years ago
The concentration of the KCN solution given in Part A corresponds to a mass percent of 0.473 %. What mass of a 0.473 % KCN solut
tiny-mole [99]
If the Ka of HCN = 5.0 x 10^-10
Since
(Ka) (Ka) - 1 x 10^ -14
then
the Kb of its conjugate base (CN-) = 2.0 X 10^-5

since
pH + pOH = 14
when the pH = 10.00
then
the pOH = 4.00
& the OH-
would then equal 1.0 X 10^-4

NaCN as a base does a hydrolysis in water:
CN- & water --> HCN & OH-
notice that equal amounts of OH- & HCN are formed

Kb = [HCN] [OH-] / [CN-]

2.0 X 10^-5 = [1.0 X 10^-4] [1.0 X 10^-4] / [CN-]

[CN-] =(1.0 X 10^-8) / (2.0 X 10^-5)

[CN-] = (5.0 X 10^-4)

that's 0.00050 Molar
which is 0.00050 moles in each liter of aqueous KCN solution
which is
0.00025 moles KCN in 500. mL of aqueous KCN solution

use molar mass of KCN, to find grams:
(0.00025 moles KCN) (65.12 grams KCN / mole) = 0.01628 grams of KCn

which is 16.3 mg of KCN
& rounded to the 2 sig figs which are showing in the Ka of HCN , "5.0" X 10^-10
your answer would be
16 mg of KCN

sorry even after making a correction in calcs , I don't get one of your answers.
the only way that I could get one of them is to pretend that yours was a 1 sig fig problem,
in which case your 16 mg would round off to 20 mg.
but you have 3 sig figs in "500. ml", & 2 sig figs in both the "pH of 10.00."
& The Ka of HCN = "5.0 x 10^-10."

it does however take 12 mg of NaCN, to make 500. mL of aqueous solution pH of 10.00. the molar mass of NaCN has the smaller molar mass of 49.00 grams per mole.
maybe they meant NaCN, but wrote KCN instead.

I hope i answered this correctly for you.
8 0
4 years ago
A substance is known to contain 2.00 g of carbon for every 5.33 g of oxygen. How many grams of carbon will be present in 55.0 g
nexus9112 [7]
First, set up a proportion:
You have 2.00 g Carbon and 7.33 g of the total substance (find it by adding 2.00g C + 5.33 g O)
You have an unknown g carbon with 55.0 g o total substance.

So:
\frac{2.00}{7.33}  =  \frac{x}{55.0}

Multiply 2.00 by 55.0 and divide the answer by 7.33 
You'll get 20.63...


8 0
3 years ago
Read 2 more answers
Ethylenediaminetetraacetic acid EDTA is 41.09% C, 5.53% H, 9.58%N, and 43.8% O. What is the empirical formula of EDTA?
sertanlavr [38]

Answer:

41.09% B N. The formula in EDTA

Explanation:

8 0
3 years ago
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