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Leno4ka [110]
3 years ago
12

Need help tremendously:)!!

Mathematics
1 answer:
Ray Of Light [21]3 years ago
8 0
For 12, do 26xpi. For 13, do 4x9.
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Find f(-2) for f(x) = 3x +4.
Bingel [31]

Answer:

f(- 2) = - 2

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x)

f(- 2) = 3(- 2) + 4 = - 6 + 4 = - 2

5 0
3 years ago
I need help ASAP PLEASE
White raven [17]
A) y= x+1
b) y= -2/3x-5
c) y=-1/2x+12
d) y= 4x-3/2
According to my calculations all the answers should be correct.
7 0
3 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
2 years ago
What is the 60th term of the sequence 2, -3, -8, -13?
aleksandrvk [35]

Answer:

  -293

Step-by-step explanation:

The first term of the arithmetic sequence is a1 = 2. The common difference is d = -3-2 = -5. The general term is ...

  an = a1 +d(n -1)

  an = 2 -5(n -1)

The 60th term is ...

  a60 = 2 -5(60 -1) = -293

4 0
2 years ago
Ill mark brainliest pl pls help me
blondinia [14]

Answer:

1. e

2. c

Step-by-step explanation:

1. e. table

The question displays a table that organizes the data

2. c

When you compare the x and y values of a relationship, in this case the b and t variables, you use a ratio.

8 0
3 years ago
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