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3 years ago

Need help tremendously:)!!

Mathematics

1 answer:

Ray Of Light [21]3 years ago

8 0

For 12, do 26xpi. For 13, do 4x9.

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The area of a parallelogram is 96 cm2. The height of the parallelogram is 4 cm less than the length of the base. What is the len

Valentin [98]

96/4=24 so the length of a standerd paralleegram is 24

4 0

3 years ago

Read 2 more answers

Which of the following equations is equivalent to 3(a + 4) – 5(a – 2) = 22?

tamaranim1 [39]

-2a+2=22

3(a+4)-5(a-2)=22
3a+12-5a-10=22
-2a+12-10=22
-2a+2=22

6 0

3 years ago

If Raj randomly chooses a point in the square below, what is the probability that point is not in the circle? Assume that pi = 3

hodyreva [135]

Answer:

49.7%

Step-by-step explanation:

A cdircle is located within a square.

Area of the circle

Area = $\pi$ $r^{2}$ , where r = 4 units.

Area Circle = 50.3 units^2

Area of the square

Area = l*w or l^2 for a square, since l = w

Area = (10 units)^2

Area = 100 units^2

Area in the square but outside the circle

This is the difference [Square minus Circle Areas]

Square minus Circle Areas = 100 - 50.3 or 49.7 units^2

Probability

The probability of picking a point in the square that is not in the circle is the ration of the two areas: [Outside Circle/Square]x100%

(49.7 units^2)/(100 units^2)x100% = 49.7%

6 0

2 years ago

Find the equation of this line. HELP

Mumz [18]

Answer:

Step-by-step explanation:

(5,4) ; (-3, -2)

$Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-2-4}{-3-5}\\\\=\frac{-6}{-8}\\\\=\frac{3}{4}$

(5,4) & m = (3/4)

y -y1 = m(x-x1)

y - 4 = (3/4)(x - 5)

$y-4=\frac{3}{4}x-\frac{3}{4}*5\\\\y-4=\frac{3}{4}x-\frac{15}{4}\\\\y=\frac{3}{4}x-\frac{15}{4}+4\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{4*4}{1*4}\\\\y=\frac{3}{4}x-\frac{15}{4}+\frac{16}{4}\\\\y=\frac{3}{4}x+\frac{1}{4}$

7 0

3 years ago

Please help! A-level maths.

astra-53 [7]

$x+y=k\implies y=k-x$

Substitute this into the parabolic equation,

$k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0$

We're told the line $x+y=k$ intersects $C$ twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

$(-7)^2-4(k+3)=49-4(k+3)>0\implies k$

We can tell from the quadratic equation that $C$ has its vertex at the point (3, 6). Also, note that

$-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5$

and

$-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6$

so the furthest to the right that $C$ extends is the point (5, 2). The line $x+y=k$ passes through this point for $2+5=k\implies k=7$ . For any value of $k$ , the line $x+y=k$ passes through $C$ either only once, or not at all.

So $7\le k$ ; in set notation,

$\{k\mid 7\le k$

4 0

3 years ago