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3 years ago

Find the radius of the circle whose equation is (x + 5)2 + (y + 8)2 = 16

Mathematics

1 answer:

Oxana [17]3 years ago

6 0

The radius is 4.

Find the radius of the circle whose equation is (x + 5)2 + (y + 8)2 = 16

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9x+rt=tx+6 solve for x

Pavlova-9 [17]

X=rt-9 There you go! there your answer
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2 years ago

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15.<br>Can someone help me?

Elina [12.6K]

Answer:

The radius, in inches, of the base of the cone will be:

r = 6 inches

Hence, option B is correct.

Step-by-step explanation:

Given

The Volume of a right circular cone V = 24 π cubic inches

The height of the cone h = 2 inches

To determine

The radius of the base of the cone r = ?

Using the formula involving Volume m, height h, and radius r of a right circular cone.

$V\:=\frac{1}{3}h\:\pi \:\:r^2\:$

substituting V = 24 π, h = 2 to find the radius r

$\left(24\pi \right)=\frac{1}{3}\left(2\right)\:\pi \:r^2$

switch sides

$\frac{1}{3}\left(2\right)\pi r^2=\left(24\pi \right)$

$\frac{1}{3}2\pi r^2=24\pi$

simplify

$2\pi r^2=72\pi$

Divide both sides by 2π

$\frac{2\pi r^2}{2\pi }=\frac{72\pi }{2\pi }$

$r^2=36$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$r=\sqrt{36},\:r=-\sqrt{36}$

Thus,

$r=6,\:r=-6$

As we know that the radius can not be negative.

Therefore, the radius, in inches, of the base of the cone will be:

r = 6 inches

Hence, option B is correct.

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2 years ago

Please help will mark brainliest

disa [49]

Answer:

The answer is C i had it on my exam on edge

Step-by-step explanation:

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2 years ago

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Mr. Bloop can high jump 5.75 feet. How far short is that of Charles Austin's record of 7 ft 10 in?

a_sh-v [17]

Answer:

5.75 feet is the same as 5 ft 9 inches (because 12 in = 1 ft and 0.75 * 12 = 9 so its 9 in). 7 ft 10 in - 5 ft 9 in = 2 ft 1 in.

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3 years ago

Please help this is i-ready!

KengaRu [80]

Answer: It will take 3 days.

Step-by-step explanation:

1 km = 1000m

12 km = 12,000m

10 * 400m = 4000m

12,000m / 1000m = 3

So, It will take 3 Days.

I hope I helped you with this I-Ready. Have a Great day!

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2 years ago

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